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Serggg [28]
3 years ago
8

What are the solutions to the equation?

Mathematics
2 answers:
solniwko [45]3 years ago
6 0
The equation is very easy to solve since there is a quadratic formula that we can apply in the problem.
With the given equation 5w2+10w=40, we can arrange the problem into 5w2+10w-40=0.
a=5, b=10, c=-40
By applying quadratic formula, the answers are 2 and -4. 
Virty [35]3 years ago
4 0

Solution:

5 w^2+10 w=40\\\\ 5(w^2+2 w)=8 \times 5 \\\\ w^2+2 w=8\\\\ w^2 + 2 w -8=0\\\\ w^2+ 4 w - 2 w -8=0\\\\ w \times(w +4)-2 \times(w+4)=0\\\\ (w-2)(w+4)=0\\\\ w-2=0 {\text{and}} w+4=0 \\\\ w=2 {\text{and}w=-4

So, the solution of the equation ,

 5 w^2+10 w=40

is , w=2 , -4.

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Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


5 0
3 years ago
Please help!!!!!!!!!!!!!!!!!
Leokris [45]

Answer:

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3 0
3 years ago
What is slope-intercept form? <br> Why do we write equations using this form?
Brums [2.3K]
Slope intercept form is y=mx+b
m=slope
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we usually use this form because we can find the slope and find where it hits the y axis.
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7 0
3 years ago
5s + 7s????????????????
natali 33 [55]

Answer:

12s

Step-by-step explanation:

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This is your answer

8 0
3 years ago
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Integral sqrt(4+3x) dx
Alisiya [41]
Let 4 + 3x = u

then 3dx = du
 
or, <span>1/3∫<span>u√</span>du
</span> 
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</span> 
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