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melisa1 [442]
3 years ago
9

Factor x3 + x2 + x + 1 by grouping.

Mathematics
2 answers:
Keith_Richards [23]3 years ago
7 0
Should be the answer
         l
         l
        v
(x+1)(x2+2)





kykrilka [37]3 years ago
4 0
To factor by grouping, you have to divide the problem into two groups:
x^3+x^2+x+1
(x^3+x^2)+(x+1)
Factor each group individually
(x^3+x^2)+(x+1)
x^2(x+1)+(x+1)
(x^2+1)(x+1)
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noname [10]

Answer:

y = 2/3x + 1/3

Step-by-step explanation:

Standard form of a line looks like y=mx+b. We already know that m is 2/3, but we don't know b. b is our y-int. With the given information, we can write this equation is point-slope form. That looks like y - y1 = m(x-x1). (x1, y1) = (1, 1) - the point given to us. So if you plug in that point to the equation, and the slope - m, it'll look like y - 1 = 2/3 (x - 1).

From here, you can just solve for y, and it'll be in standard form. I would distribute 2/3 first.

y - 1 = 2/3x - 2/3

Then, add 1 to both sides.

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3 years ago
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drek231 [11]

Answer:

1137

Step-by-step explanation:

5675+453

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Now

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