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3 years ago

Separate 846 into 3 parts so that the second part is twice the first part and the third part is triple the second part.

Mathematics

2 answers:

viva [34]3 years ago

6 0

846/3=x=2x=6x is the anwser

Vesna [10]3 years ago

4 0

846/3=x+2x+6x
You must be a high schooler lol

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C(squared)L(squared) + 100v(squared) = 100c(squared)<br>I have to solve for L

jeyben [28]

First subtract 100v² from both sides to get:

C²L²=100c²-100v²

Then divide both sides by C²:

L²=(100c²-100v²)/C²

Then take the square root of both sides:

L=+ or - the square root of (100c²-100v²)/C²

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2 years ago

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What is 4% of 50% of 5

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Answer:

4% of 50% of 5 is 0.1

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3 years ago

What is the formula to the area of a triangle?

Lorico [155]

Answer:

(Base x height) x 1/2

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2 years ago

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The real number square root of 16 belongs to which sets of numbers?

klasskru [66]

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The square root of 16 is a rational number. The square root of 16 is 4, an integer

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2 years ago

Of 560 marbles in a bag, 65% are red and the rest are blue. After 28 red marbles are replaced with blue ones, how many blue marb

jonny [76]

Answer: The answer is 400 blue marbles.

Step-by-step explanation: Given that there are 560 marbles in a bag, out of which 65% are red and rest are blue.

So, number of red marbles is

$n_r=65\%\times 560=\dfrac{65}{100}\times 560=364,$

and number of blue marbles is

$n_b=560-364=196.$

Now, if 28 red marbles are replaced by blue marbles, the the new number of red and blue marbles will be

$n_r^\prime=364-28=336~~~\textup{and}~~~n_b^\prime=196+28=224.$

Now, to get 65% of the marbles blue, we need to add some more blue marbles to the bag. Let 'x' number of blue marbles are added to the bag, then

$65\%\times (560+x)=224+x\\\\\Rightarrow \dfrac{65}{100}\times (560+x)=224+x\\\\\Rightarrow 13(560+x)=20(224+x)\\\\\Rightarrow 7280+13x=4480+20x\\\\\Rightarrow 7x=2800\\\\\Rightarrow x=400.$

Thus, 400 blue marbles need to be added to the bag.

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3 years ago

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