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mart [117]
4 years ago
7

assuming that the DVD player loses 60% of its value every year it is in a video store suppose the initial value of the DVD playe

r was $80 what multiplier would you use to calculate the DVD players new valued
Mathematics
1 answer:
Alik [6]4 years ago
5 0
The multiplier you would use to find the new value would be 0.4.

The reason for this is that 100%-60% =40%. This is the part of the value it will keep. 40% is the same as 0.4.

This decimal represents the part of the original price that is it still worth.

The multiplier is 0.4 because that it what you would multiply $80 by to find the new value.
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A number that can be written as a fraction of two interfere is called a _____ number.it has a decimal representation that termin
goblinko [34]

Answer: imijijjjjntjiifrjifr line juce

Step-by-step explanation:

7 0
3 years ago
It takes Roberto eight hours longer than Paula to repair a transmission. If it takes three hours to do the job if they work toge
Stells [14]

Answer:

Paula = 4 hours

Roberto = 12 hours

Step-by-step explanation:

Time taken by Paula = x

Time taken by Roberto = x +. 8

Paula's rate = 1/x

Roberto's rate = 1/(x + 8)

Combined rate = 1/3

Time it takes each if them working alone ;

Paula's rate + Roberto's rate = combined rate

1 /x + 1 / (x +8) = 1/3

Take the L. C. M

((x+8) + x) / x(x+8) = 1/3

(2x + 8) / x(x + 8) = 1/3

3(2x + 8) = x(x + 8)

6x + 24 = x² + 8x

x² + 8x - 6x - 24 = 0

x² + 2x - 24 = 0

Solving the quadratic equation :

x² + 6x - 4x - 24 = 0

x(x + 6) - 4(x + 6) = 0

(x - 4) = 0 or (x + 6) = 0

x = 4 or x = - 6

Time taken cannot be negative

Hence, x = 4

Hence, working alone, it takes ;

Time taken by Paula = 4

Time taken by Roberto = 4 + 8 = 12

6 0
3 years ago
Simplify this equation please.
Sauron [17]
\dfrac{\csc^2\theta-3\csc\theta+2}{\csc^2\theta-1}

Identity:

\sin^2\theta+\cos^2\theta=1\implies1+\cot^2\theta=\csc^2\theta

So we can rewrite the denominator to get

\dfrac{\csc^2\theta-3\csc\theta+2}{\cot^2\theta}

Multiply numerator and denominator by \sin^2\theta. Several terms will cancel since \sin\theta\csc\theta=1. Also, \cot\theta=\dfrac{\cos\theta}{\sin\theta}. We get

\dfrac{1-3\sin\theta+2\sin^2\theta}{\cos^2\theta}

Factorize the numerator, and write \cos in terms of \sin in the denominator to factorize it further to get

\dfrac{(1-\sin\theta)(1-2\sin\theta)}{\cos^2\theta}=\dfrac{(1-\sin\theta)(1-2\sin\theta)}{1-\sin^2\theta}=\dfrac{(1-\sin\theta)(1-2\sin\theta)}{(1-\sin\theta)(1+\sin\theta)}


The 1-\sin\theta factors cancel, leaving you with

\dfrac{1-2\sin\theta}{1+\sin\theta}

which you could simplify a bit further by writing

\dfrac{1+\sin\theta-3\sin\theta}{1+\sin\theta}=1-\dfrac{3\sin\theta}{1+\sin\theta}
3 0
4 years ago
How do i find the perimeter of a square
Galina-37 [17]
Add Al the sides of the square
7 0
3 years ago
Read 2 more answers
Can u solve these 4 me?
Ber [7]

So for this:

(-1/3+-0.3/3+1) ^2

(-1/3-0.1+1)^2

(1-1.3/3)^2

(1-0.433333)^2

0.566667^2

Answer: 0.321111

0.32

8 0
3 years ago
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