Answer:
$33.81
Step-by-step explanation:
(3 * 2.49) + (2 * 3.19) + (4 * 4.99)
7.47 + 6.38 + 19.96 = 33.81
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Answer:
Y= 2e^(5t)
Step-by-step explanation:
Taking Laplace of the given differential equation:
s^2+3s-10=0
s^2+5s-2s-10=0
s(s+5)-2(s+5) =0
(s-2) (s+5) =0
s=2, s=-5
Hence, the general solution will be:
Y=Ae^(-2t)+ Be^(5t)………………………………(D)
Put t = 0 in equation (D)
Y (0) =A+B
2 =A+B……………………………………… (i)
Now take derivative of (D) with respect to "t", we get:
Y=-2Ae^(-2t)+5Be^(5t) ....................... (E)
Put t = 0 in equation (E) we get:
Y’ (0) = -2A+5B
10 = -2A+5B ……………………………………(ii)
2(i) + (ii) =>
2A+2B=4 .....................(iii)
-2A+5B=10 .................(iv)
Solving (iii) and (iv)
7B=14
B=2
Now put B=2 in (i)
A=2-2
A=0
By putting the values of A and B in equation (D)
Y= 2e^(5t)
Answer:
i don't know but I think question 1 is 64
Answer:
We are given the lengths of the two segments of the line. Using the addition postulate we can obtain the segment of the entire line.
Did you draw out the diagram. We know that the three points are collinear.
Hope this helps
Step-by-step explanation:
Answer:
I believe the answer is D?
Step-by-step explanation:
