Well, you distribute the 8 to both terms since it is being multiplied.
8 * y = 8y
8 * 3 = 24
so the ending equation should be 8y + 24
X + (x + 2) + (x + 4) + (x + 6) = 3(x + 6)...combine like terms
4x + 12 = 3x + 18
4x - 3x = 18 - 12
x = 6
x + 2 = 6 + 2 = 8
x + 4 = 6 + 4 = 10
x + 6 = 6 + 6 = 12
so ur 4 numbers are : 6,8,10,and 12...and the sum of all of them (36) = 3 times the largest (3 x 12) = 36
Answer:
let the third side be x
using pythagoras theorem we get
(7)^2+(6)^2=(x)^2
49+36=x^2
√(85)=x
x=9.21
Answer:
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Answer:
144
Step-by-step explanation:
Remark
Well you could do this the brute force way. 32 is the nineth term in the series. Sum = 0 + 4 + 8 + 12 + ... 32 = 144. That will get you an answer.
This works unless you are asked for the 44434th term. Then you better use a formula. Even the hundredth term would be trouble.
Step One
Find d
d is given as 4
Step 2
find n. There are 9 terms. The 9 is given.
Step 3
Find the ninth term.
<em><u>Givens</u></em>
a1 = 0
n = 9
d = 4
<em><u>Formula for the 9th term: </u></em>a9 = a1 + (n - 1)*d
Substitute and Solve
a9 = 0 + (9 - 1)*4
a9 = 8*4 = 32
Step 4
Find the sum of the first 9 terms
Sum = (a1 + a9)*n/2
Sum = (0 + 32)*9/2
Sum = 32 * 9/2
Sum = 32 * 4.5
Sum = 144