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3 years ago

8

Write a real world problem I which you would divide decimals

2 answers:

Dominik [7]3 years ago

7 0

Three point five divided by two equals one point five

Alik [6]3 years ago

3 0

Bob had $5.55 he had to share it amount four friends plus himself. How much would each person recieve

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What is the equivalent exponential form of the fourth root of x?

mart [117]

I hope this helps you

7 0

3 years ago

F(x)= 25 + 4x How would you solve this please show your work. ASAP

kvv77 [185]

Ok so f(x) really just means y so ur equation is
y=4x+25

7 0

3 years ago

The expression 10a+6c gives the cost (in dollars) for a adults and c children to eat at a buffet restaurant. A. The cost for 1 a

Liono4ka [1.6K]

Answer: The total cost is $\$62$ assuming the cost for 1 adult is $\$5$ and the cost for 1 child is $\$2$

Step-by-step explanation:

Assuming the cost for 1 adult is $\$5$ and the cost for 1 child is $\$2$ :

$a=\$5$ and $c=\$2$

Then the expression that gives the total cost $10 a+6c$ is solved as:

$10(\$5)+6(\$2)=\$62$

4 0

3 years ago

Ronnie bought six ice cream cones for himself and his friends $.17 tax was added to the price of each coin the total cost was $1

brilliants [131]

Answer:

The price for one cone before tax is $2.26.

Step-by-step explanation:

The tax for each cone is $.17

Ronnie buys six cones. The total tax for the cones is 6 X $.17 = $1.02

Next, we subtract the total taxes from the total price $14.58 - $1.02 = $13.56

So Ronnie owed $13.56 for the six cones BEFORE taxes. We takes this amount and divide it by six to get the cost for one cone.

$13.56 / 6 = $2.26 per cone.

Check our work

Purchase one cone for $2.26 plus $.17 cents tax = $2.43 total cost per cone.

6 cones at $2.43 each would be 6 X $2.43 = $14.58.

This matches the total bill from the story problem.

4 0

3 years ago

In the first week students at RSM solved 25 percent of their monthly quota of problems. In the second week, they solved 110 perc

natka813 [3]

Answer:

The number of problems solved = 2000

Step-by-step explanation:

Let us assume the monthly quota of problems be x

number of problem solved in first week = 25 % of x = $0.25x$

number of problems solved in 2nd week = 110% of (problems solved in 1st week)

= $1.10 (0.25x)$

= $0.275x$

number of problem solved 3rd week= 60% of ( problems solved in 1st and 2nd week)

= $0.60(0.25x+0.275x)$

= $0.60(0.525x)$

= $0.315x$

number of problem solved in 4th week = $320$

now we have

number of problems solved in ll 4 weeks = x

$0.25x +0.275x+0.315x+320=x$

$0.84x+320=x$

$320=x-0.84x$

$320=0.16 x$

$x=\frac{320}{0.16}$

$x=2000$

Hence the number of problems solved = 2000

7 0

3 years ago