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polet [3.4K]
3 years ago
11

What is the equation of a line parallel to the line y = 4x + 7 and passes through the point (3, 0)?

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
5 0
Two lines to be parallel their slopes have to be equal. 

so m1 = m = 4


y = mx + b ( Slope intercept form)


y = 4x + b

(3,0) is on the line:

0 = 12 + b

b = -12

y = 4x - 12 
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Sladkaya [172]

Answer:

54

Step-by-step explanation:

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3 years ago
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Among all right circular cones with a slant height of 24​, what are the dimensions​ (radius and​ height) that maximize the volum
aleksklad [387]

Answer:

5571.99

Step-by-step explanation:

We need to use the Pythagorean theorem to solve the problem.

The theorem indicates that,

r^2+h^2=24^2 \\r^2+h^2=576\\r^2=576-h^2

Once this is defined, we proceed to define the volume of a cone,

v=\frac{1}{3}\pi r^2 h

Substituting,

v=\frac{1}{3} \pi (576-h^2)h\\v=\frac{1}{3} \pi (576h-h^3)

We need to find the maximum height, so we proceed to calculate h, by means of its derivative and equalizing 0,

\frac{dv}{dh} = \frac{1}{3} \pi (576-3h^2)

\frac{dv}{dh} = 0 then \rightarrow \frac{1}{3}\pi(576-3h^2)=0

h_1=-8\sqrt{3}\\h_2=8\sqrt{3}

<em>We select the positiv value.</em>

We have then,

r^2 = 576-(8\sqrt3)^2 = 384\\r=\sqrt{384}

We can now calculate the maximum volume,

V_{max}= \frac{1}{3}\pi r^2 h = \frac{1}{3}\pi (\sqrt{384})^2 (8\sqrt{3}) = 5571.99

4 0
3 years ago
Please help!!
valkas [14]

A calculator can show you the answer to these very quickly.

\dfrac{7.488\cdot 10^{-8}}{3.12\cdot 10^{2}}=\dfrac{7.488}{3.12}\times 10^{(-8-2)}\\\\=2.4\cdot 10^{-10}

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Step-by-step explanation: tRUST ME ON THIS

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b)
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34 sq m
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3 years ago
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