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garri49 [273]
2 years ago
8

HELPPPP meememmee pls

Mathematics
2 answers:
Blababa [14]2 years ago
8 0

Answer:

-27

Step-by-step explanation:

subtract 8 from 35

Sav [38]2 years ago
4 0

Answer:

-27

Hope this helps.

I really got nothing else to say so um.

Goodbye

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Step-by-step explanation:

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X/5=1/(x+4) solve for x
solmaris [256]

ANSWER:

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1) cross multiply

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3 years ago
Use the sum and difference identities to find the exact values of the sine, cosine, and tangent of the angle. . 165 = 135 + 30
Serhud [2]
So lets get to the problem 

<span>165°= 135° +30° </span>

<span>To make it easier I'm going to write the same thing like this </span>
<span>165°= 90° + 45°+30° </span>

<span>Sin165° </span>
<span>= Sin ( 90° + 45°+30° ) </span>
<span>= Cos( 45°+30° )..... (∵ Sin(90 + θ)=cosθ </span>
<span>= Cos45°Cos30° - Sin45°Sin30° </span>

<span>Cos165° </span>
<span>= Cos ( 90° + 45°+30° ) </span>
<span>= -Sin( 45°+30° )..... (∵Cos(90 + θ)=-Sinθ </span>
<span>= Sin45°Cos30° + Cos45°Sin30° </span>


<span>Tan165° </span>
<span>= Tan ( 90° + 45°+30° ) </span>
<span>= -Cot( 45°+30° )..... (∵Cot(90 + θ)=-Tanθ </span>
<span>= -1/tan(45°+30°) </span>
<span>= -[1-tan45°.Tan30°]/[tan45°+Tan30°] </span>

<span>Substitute the above values with the following... These should be memorized </span>
<span>Sin 30° = 1/2 </span>
<span>Cos 30° =[Sqrt(3)]/2 </span>
<span>Tan 30° = 1/[Sqrt(3)] </span>
<span>Sin45°=Cos45°=1/[Sqrt(2)] </span>
<span>Tan 45° = 1</span>
4 0
3 years ago
Question 2(Multiple Choice Worth 5 points) (05.01)A poster is shown below: A rectangle is shown. The length of the rectangle is
Karo-lina-s [1.5K]

Answer:

The enlargement will be 30 ft by 7.5 ft.

Step-by-step explanation:

A scale drawing is a larger or smaller version of an object. To find the dimensions of the new drawing, multiply each measurement by the scale factor. The scale factor here is 5/2 or 2.5.

12(2.5)=30 ft

3(2.5)=7.5 ft



7 0
3 years ago
Which of these statements is true for 89.033​
grigory [225]
Maybe if you payed attention in class you would know.
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