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stich3 [128]
3 years ago
5

6b < 36 or 2b + 12 > 6

Mathematics
1 answer:
Step2247 [10]3 years ago
4 0

Answer:

-3 < b < 6

Step-by-step explanation:

6b < 36 or 2b + 12 > 6

b < \frac{36}{6} or 2b > 6 - 12

b < 6 or b > -3

Simplifying this becomes;

-3 < b < 6

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Lynna [10]

Answer:

4w^2 +4w+1

this is the product.

Step-by-step explanation:

7 0
3 years ago
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Find the squares of (m-1)​
Alchen [17]

Answer:

Solution

verified

Verified by Toppr

m

2

−3m−1=0

m

2

−3m=1 → (1)

Third term =(

2

1

coeeficientofm)

2

(

2

1

×(−3))

2

=(

2

−3

)

2

=

4

9

Adding

4

9

to both sides of equation (1), we get

m

2

−3m+

4

9

=1+

4

9

∴ m

2

−3m+

4

9

=

4

4+9

∴ (m−

2

3

)

2

=

4

13

Taking square roots on both sides

∴ m−

2

3

=±

2

13

∴ m=

2

3

+

2

13

or m=

2

3

−

2

13

m=

2

3+

13

,

2

3−

13

are the roots of the given quadratic equation.

8 0
3 years ago
If f(1)=6f(1)=6 and f(n)=nf(n-1)-4f(n)=nf(n−1)−4 then find the value of f(3)f(3).
alekssr [168]

Answer:

49

Step-by-step explanation:

6 0
3 years ago
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What is the missing number?
JulsSmile [24]

Answer:

y = 2^{x}

Step-by-step explanation:

Given the above data for x and y.

From the algebraic expression;

y = 2^{x}

We can deduce that the value of y is equal to two (2) raise to the power of x.

When x = 1, y = 2

y = 2^{x}

y = 2^{1}

y = 2

When x = 2, y = 4

y = 2^{x}

y = 2^{2}

y = 4

When x = 3, y = 8

y = 2^{x}

y = 2^{3}

y = 8

The above calculations can be used to determine the other values of y with respect to x.

3 0
3 years ago
SOMEONE PLZ ANSWER THE NUMBERS!!!!
Sonbull [250]

Answer: The median for the set of numbers is B. 11.

Step-by-step explanation: Order numbers least to greatest. 4,4,9,10,12,23,68,70

Find the middle numbers:

10, 12.

Find the number in between 10 and 12.

= 11

6 0
3 years ago
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