The genotypes would be bbTT X BbTt
Assuming that bark color is represented by B (b) allele and height is represented by T (t) allele.
Since the traits show simple dominance: blue (B) of dominant over purple (b) and tall (T) is dominant over short (t)
- The genotype of a tree that is purebred purple (bb) and tall (TT) would be bbTT
- The genotype of a tree that is heterozygous for both trait would be BbTt
- Thus, the cross would be bbTT x BbTt
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