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Goshia [24]
3 years ago
14

Based on data from a car bumper sticker​ study, when a car is randomly​ selected, the number of bumper stickers and the correspo

nding probabilities are as shown below. complete parts​ (a) through​ (d)
Mathematics
1 answer:
Viktor [21]3 years ago
7 0
<span> Does the given information describe a probability​ distribution? </span>

Yes

<span> Assuming that a probability distribution is​ described, find its mean and standard deviation. </span>

The mean is equal to 0.6. The standard deviation is equal to 1.5

<span> Use the range rule of thumb to identify the range of values for usual numbers of bumper stickers. </span>

<span>The maximum usual value is 3.5.</span>

<span>max: μ + 2σ = 0.578 + 2(1.462161414) = 3.502322828</span>

<span>The minimum usual value is 0.</span>

<span>min: μ – 2σ = 0.578 – 2(1.462161414) = -2.346322828</span>

<span> Is it unusual for a car to have more than one bumper​ sticker? Explain. </span>

No, because the probability of having more than one bumper sticker is equal to 0.120 that is greater that 0.05

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3 years ago
Please help me it one question and give explanation because a lot of people lie and make me get wrong:(
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3 years ago
What prime numbers make 32 being added up
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29 and 3

13 and 19

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3 0
3 years ago
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Alex_Xolod [135]
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5 0
2 years ago
The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) 5x/x^2
Olegator [25]

Given :

The percent of concentration of a certain drug in the bloodstream x hours after the drug is administered is given by K(x) = \dfrac{5x}{x^2+9}.

To Find :

Find the time at which the concentration is a maximum. b. Find the maximum concentration.

Solution :

For maximum value of x, K'(x) = 0.

K'(x) = \dfrac{5(x^2+9)- 5x(2x)}{(x^2+9)^2}=0\\\\5x^2+45-10x^2=0\\\\5x^2 = 45\\\\x = \pm 3

Since, time cannot be negative, so ignoring x = -3 .

Putting value of x = 3, we get, K(3) = 15/( 9 + 9) = 5/6

Therefore, maximum value drug in bloodstream is 5/6 at time x = 3 units.

Hence, this is the required solution.

5 0
3 years ago
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