we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form
or 
where
k is the constant of variation
in this problem we have
the point 
so

substitute


therefore
<u>the answer is</u>

To solve for the other leg, you need to use Pythagorean theory.
The theory states that C^2 = A^2 + B^2
In your case, you have to solve for B.
C = 40 (hypotenuse) A = 24 (leg 1)
The formula rewritten for B is

Now, you can solve.

Therefore, B = 32.
So the second leg is 32 feet.
Answer:
i dont now
Step-by-step explanation:
ed
Answer: See explanation
Step-by-step explanation:
You didn't give the expressions but here are some expressions
a. ✓4x²y^4. 1. 2x✓y
b. ✓8x²y. 2. 2y✓2x
c. ✓4x²y. 3. 2xy²
d. ✓16xy². 4. 2x✓2y
e. ✓8xy². 5. 4y✓x
a. ✓4x²y^4 = ✓4 × ✓x² × ✓y^4
= 2 × x × y²
= 2xy²
Therefore, ✓4x²y^4 = 2xy²
b. ✓8x²y = ✓8 × ✓x² × ✓y
= ✓4 × ✓2 × ✓x² × ✓y
= 2 × ✓2 × x × ✓y
= 2x✓2y
Therefore, ✓8x²y = 2x✓2y
c. ✓4x²y = ✓4 × ✓x² × ✓y
= 2 × x × ✓y
= 2x✓y
Therefore, ✓4x²y = 2x✓y
d. ✓16xy² = ✓16 × ✓x × ✓y²
= 4 × ✓x × y
= 4y✓x
Therefore, ✓16xy² = 4y✓x
e. ✓8xy² = ✓8 × ✓x × ✓y²
= ✓4 × ✓2 × ✓x × ✓y²