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NNADVOKAT [17]
3 years ago
12

The first company charges $50 for a service call,plus an additional $36 per hour for labor.The second company charges $35 for a

service call,plus an additional $39 per hour of labor.At how many hours will the two companies charge the same amount of money?
Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
8 0

Answer:

5 hours

Step-by-step explanation:

So what you have to do is set the two equal to one another and solve for x

50+36x=35+39x

-35 -35

15+36x=39x

-36x -36x

15= 3x

/3 /3

5=x

liberstina [14]3 years ago
6 0

Answer: it would take 5 hours of labour before you pay the same amount for both companies.

Step-by-step explanation:

Let x represent the number of hours of labour that you pay for company A or company B

Let y represent the total amount paid for x hours of labour at company A

Let z represent the total amount paid for x hours of labour at company B

company A charges $50 for a service call plus an additional $36 per hour for labor.. This means that the total amount for x hours of labour would be

y = 36x + 50

company B charges $35 for a service call plus an additional $39 per hour of labor. This means that the total amount for x hours would be

z = 39x + 35

To determine the number of hours of labour before the amount for both companies becomes the same, we would equate y to z. It becomes

36x + 50 = 39x + 35

39x - 36x = 50 - 35

3x = 15

x = 5

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Answer:

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x = 165/80 = 2.0625 hours, which is also 2 hours and 3 minutes.

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What is -3 times x squared?
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What is -3 times x squared?-9x 
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Solve the equation using the Zero-Product Property (X-9)(x+7)=0
aleksandr82 [10.1K]
(x-9)(x+7)=0
x-9=0 or x+7=0
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4 0
3 years ago
Which set of ordered pairs does not represent a function? O {(-3,-9), (7,9), (9, 1), (7,3)} O {(-3,8),(-6,5), (-5, -6), (1,-6)}
kvasek [131]

Answer:

The first set of ordered pairs is not a function.

Step-by-step explanation:

The X value of 7 repeats, which means that it is not a function

7 0
3 years ago
Read 2 more answers
Imagine an experiment having three conditions and 20 subjects within each condition. The mean and variances of each condition ar
xxTIMURxx [149]

Answer:

1. Mean square B= 5.32

2. Mean square E= 16.067

3. F= 0.33

4. p-value: 0.28

Step-by-step explanation:

Hello!

You have the information of 3 groups of people.

Group 1

n₁= 20

X[bar]₁= 3.2

S₁²= 14.3

Group 2

n₂= 20

X[bar]₂= 4.2

S₂²= 17.2

Group 3

n₃= 20

X[bar]₃= 7.6

S₃²= 16.7

1. To manually calculate the mean square between the groups you have to calculate the sum of square between conditions and divide it by the degrees of freedom.

Df B= k-1 = 3-1= 2

Sum Square B is:

∑ni(Ÿi - Ÿ..)²

Ÿi= sample mean of sample i ∀ i= 1,2,3

Ÿ..= general mean is the mean that results of all the groups together.

General mean:

Ÿ..= (Ÿ₁ + Ÿ₂ + Ÿ₃)/ 3 = (3.2+4.2+7.6)/3 = 5

Sum Square B (Ÿ₁ - Ÿ..)² + (Ÿ₂ - Ÿ..)² + (Ÿ₃ - Ÿ..)²= (3.2 - 5)² + (4.2 - 5)² + (7.6 - 5)²= 10.64

Mean square B= Sum Square B/Df B= 10.64/2= 5.32

2. The mean square error (MSE) is the estimation of the variance error (σ_{e}^2 → S_{e} ^{2}), you have to use the following formula:

Se²=<u> (n₁-1)S₁² + -(n₂-1)S₂² + (n₃-1)S₃²</u>

                        n₁+n₂+n₃-k

Se²=<u> 19*14.3 + 19*17.2 + 19*16.7 </u>= <u>  915.8   </u>  = 16.067

                 20+20+20-3                  57

DfE= N-k = 60-3= 57

3. To calculate the value of the statistic you have to divide the MSB by MSE

F= \frac{Mean square B}{Mean square E} = \frac{5.32}{16.067} = 0.33

4. P(F_{2; 57} ≤ F) = P(F_{2; 57} ≤ 0.33) = 0.28

I hope you have a SUPER day!

3 0
3 years ago
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