Answer:
<em>The area of the trapezium is 168</em>
Step-by-step explanation:
<u>Area of a Trapezoid</u>
Given a trapezoid of parallel bases b1 and b2, and height h, the area is calculated with the formula:
The trapezoid in the figure has b1=15 and b2=27. We need to find the height. If we focus on triangle BCD, we can calculate the height as the distance EC by using the Pythagora's Theorem:
The side BC can be found as half the difference of the bases:
Solving for EC:
Now we have the height, calculate the area:
A = 168
The area of the trapezium is 168
Answer:
Step-by-step explanation:
From the figure attached,
Given:
Lines AB and CD are intersecting each other at a point E.
To prove:
∠ACB ≅ ∠DEB
Statements Reasons
1). ∠AEC + ∠BEC = 180° 1). Linear pair theorem
2). ∠DEB + ∠BEC = 180° 2). Linear pair theorem
3). ∠AEC + ∠BEC = ∠DEB + ∠BEC 3). Transitive property of equality
4). ∠AEC = ∠DEB 4). Subtraction property of equality
Answer:
Step-by-step explanation:
Domain:
![\dfrac{x^2+9y^2}{x-3y}+\dfrac{6xy}{3y-x}=\dfrac{x^2+9y^2}{x-3y}+\dfrac{6xy}{-(x-3y)}\\\\=\dfrac{x^2+9y^2}{x-3y}-\dfrac{6xy}{x-3y}=\dfrac{x^2+9y^2-6xy}{x-3y}\\\\=\dfrac{x^2-2(x)(3y)+(3y)^2}{3y-x}=\dfrac{(x-3y)^2}{3y-x}\\\\=\dfrac{\bigg[-1(3y-x)\bigg]^2}{3y-x}=\dfrac{(-1)^2(3y-x)^2}{3y-x}\\\\=\dfrac{1(x-3y)(x-3y)}{x-3y}=x-3y](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%5E2%2B9y%5E2%7D%7Bx-3y%7D%2B%5Cdfrac%7B6xy%7D%7B3y-x%7D%3D%5Cdfrac%7Bx%5E2%2B9y%5E2%7D%7Bx-3y%7D%2B%5Cdfrac%7B6xy%7D%7B-%28x-3y%29%7D%5C%5C%5C%5C%3D%5Cdfrac%7Bx%5E2%2B9y%5E2%7D%7Bx-3y%7D-%5Cdfrac%7B6xy%7D%7Bx-3y%7D%3D%5Cdfrac%7Bx%5E2%2B9y%5E2-6xy%7D%7Bx-3y%7D%5C%5C%5C%5C%3D%5Cdfrac%7Bx%5E2-2%28x%29%283y%29%2B%283y%29%5E2%7D%7B3y-x%7D%3D%5Cdfrac%7B%28x-3y%29%5E2%7D%7B3y-x%7D%5C%5C%5C%5C%3D%5Cdfrac%7B%5Cbigg%5B-1%283y-x%29%5Cbigg%5D%5E2%7D%7B3y-x%7D%3D%5Cdfrac%7B%28-1%29%5E2%283y-x%29%5E2%7D%7B3y-x%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%28x-3y%29%28x-3y%29%7D%7Bx-3y%7D%3Dx-3y)
Used:
The distributive property: a(b + c) = ab + ac
(a - b)² = a² - 2ab + b²
Answer:
Step-by-step explanation:
(-4,0) (0,3)
(3-0)/(0+4)= 3/4
y - 0 = 3/4(x + 4)
y = 3/4x + 3
The answer is A, the flat rate is the y-intercept and hourly is the slope
