Find the area and perimeter of a rectangle with a length of 3x + 2 and a width of 4x + 3.
2 answers:
Answer:
Perimeter =<em>14x+10</em>
<em>Area =</em> =+17x+6
Step-by-step explanation:
Area of a rectangle=Length *width
=(3x+2)(4x+3)
=3x(4x+3)+2(4x+3)
=+9x+8x+6
=+17x+6
- Then find x using quadratic equation and substitute the values
Perimeter of a rectangle =2(length +width)
=2(3x+2+4x+3)
=6x+4+8x+6
=<em>14x+10</em>
<em>Hope you got it</em>
<em>If you have any problem just ask me</em>
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Answer:
C
Step-by-step explanation:
I think I will answer the question the your attachment because it has full information.
The function is: y = 3*
a. The function decreases
Wrong, because the base number is 2 and it is greater than 0. The function will go up
b. y=intercept of (0.2)
Wrong, Let substitute x =2 into the function: y = 3* = 12
c. if x increase by 1, the value of y will double
Because the base number is 2. For example:
- If x = 2, y = 3*
= 12
- If x =3, y =3*
=(3*
d. contains the point (2,4)
Wrong, Let substitute x =4 into the function: y = 3* = 48
So we choose C