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Diano4ka-milaya [45]
3 years ago
9

Graph the function x+y=6 -Can someone help and tell me how would i graph this?

Mathematics
1 answer:
slamgirl [31]3 years ago
7 0

This is how you would graph your function.

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Which statement is true of the function f(x) = Negative RootIndex 3 StartRoot x EndRoot? Select three options.
ycow [4]

Answer:

Options (2), (3) and (4) are correct.

Step-by-step explanation:

The given function is f(x) = -\sqrt[3]{x}

1). First derivative of the function = f'(x) = \frac{d}{dx}(-\sqrt[3]{x} )

  f'(x) = -\frac{1}{3}(x)^{-\frac{2}{3}}

  Since derivative is negative, function will be decreasing everywhere.

  Therefore, Option (1) is incorrect.

2). Since value of the function is true for every value of all real values of x.

  Domain of the function is (-∞, ∞).

  Therefore, Option (2) is correct.

3). For the given domain, range of the function will be all real values of y Or (-∞, ∞)

  Therefore, Option (3) is correct.

4). Function 'f' when reflected across x axis, equation of the reflected function will be g(x) = \sqrt[3]{x}.

 Therefore, Option (4) is correct.

5). For a point (3, -27),

  -27 = -\sqrt[3]{3}

  Therefore, Option (5) is incorrect.

8 0
3 years ago
The difference of eight and twice a number
Over [174]

Answer:

8 - 2x

Step-by-step explanation:

Let x be the unknown number

difference is subtraction

8 - 2x

4 0
3 years ago
Which point-slope equation represents a line that passes through (3,-2) with a slope of -4/5?
Viefleur [7K]

Answer:

y + 2 = -4/5 (x - 3)

Step-by-step explanation:

y - y1 = m (x - x1). Put in your points for y1 and x1, and always remember to flip your signs.

unfortunately, I don't know why that isn't one of your answers, so sticking with the positive 2 I would choose y+2=- (- 3) if I were you. Looks like the -4/5 disappeared somehow?

Hope this helps

8 0
3 years ago
What is the lcm of 9and 4
Nadusha1986 [10]
They are relatively prime so lcm (4,9)=9*4=36
3 0
3 years ago
Read 2 more answers
7 1/2 divided by 1 1/2 = 5 How to check the answer
Gnom [1K]

Answer:

We verified that the equation 7\frac{1}{2}\div1\frac{1}{2}=5 has both sides equal.

Step-by-step explanation:

We need to solve and verify: 7\frac{1}{2}\div1\frac{1}{2}=5

Solving:

7\frac{1}{2}\div1\frac{1}{2}=5

Converting into improper fractions

\frac{15}{2}\div\frac{3}{2}=5

Converting division sign into multiplication and reversing 3/2 i.e

\frac{15}{2}\times\frac{2}{3}=5

Now simplifying

\frac{15}{3}=5 \\5=5

So, We verified that the equation 7\frac{1}{2}\div1\frac{1}{2}=5 has both sides equal.

7 0
3 years ago
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