1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andrej [43]
9 months ago
7

21. To find a baseball pitcher's earned run average (ERA), you can use the formula Ei=9r, in which E represents ERA, i represent

s the number of innings pitched, and r represents the number of eamed runs allowed. Please answer the following and separate your answers by a comma (EX: 10, 11) Solve the equation for E. What is the pitcher's ERA if he allows 5 earned runs in 18 innings pitched?
Mathematics
1 answer:
antoniya [11.8K]9 months ago
7 0

Answer:

E = 2.5

Explanation:

The initial eqauation is E=?r

To solve for E, we need to divide both sides by i as:

\begin{gathered} E\cdot i=9\cdot r \\ \frac{E\cdot i}{i}=\frac{9\cdot r}{i} \\ E=\frac{9\cdot r}{i} \end{gathered}

Now, to calculate the pitcher's ERA, we need to replace r by 5 earned runs and i by 18 innings pitched. Then:

E=\frac{9\cdot5}{18}=2.5

Therefore, the pitcher's ERA is equal to 2.5

9

You might be interested in
Please help me ASAP please
lianna [129]

Answer:

Alright so basically

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the volume of a sphere that has a 12m diameter?
lesya [120]
Volume of Sphere = (4/3)*(pi)*(r^3)
 
                            r = (D/2) = 6 m
                        
                              =<span>(4/3)*(pi)*((6^3)

                              = 904.7786.. m^3
I hope this helps.</span>
5 0
3 years ago
Three cans of tuna costs $1.50. What is the cost of one can of tuna
lord [1]
The cost of one can of tuna is $1.50/3, or $0.50 per can.
6 0
3 years ago
Read 2 more answers
What is the mode? please explain
maxonik [38]

<em>i</em><em> </em><em>think</em><em> </em><em>it</em><em> </em><em>is</em><em><u> </u></em><em><u>8</u></em>

Step-by-step explanation:

hope this helps! ;)

8 0
3 years ago
Read 2 more answers
Assume that the wavelengths of photosynthetically active radiations (PAR) are uniformly distributed at integer nanometers in the
trasher [3.6K]

Answer:

Mean=685

Variance=36.7

Step-by-step explanation:

The mean of uniform discrete distribution can be expressed as the average of the boundaries

mean=( b+a)/2

The variance of uniform discrete distribution can be expressed as the difference of the boundaries decreased by 1 and squared, decreased by 1 and divided by 12.

σ²=[(b-a+1)^2 - 1]/12

We were given the wavelength from from 675 to 695 nm which means

a= 675, b= 695

We can now calculate the mean by using the expresion below

mean=( b+a)/2

Mean=( 675 + 695)/2

=685

The variance can be calculated by using the expression below

σ²=[(b-a+1)^2 - 1]/12

σ²=[(695-675+1)^2 -1]/12

σ²=440/12

σ²=36.7

Therefore, the the mean and variance, of the wavelength distribution for this radiation are 685 and 36.7 respectively

7 0
3 years ago
Other questions:
  • In circle Y, What is mTU?
    5·2 answers
  • James is X years older than Alex. Alex is X years older than Kim. James is twice as old as Kim. Alex is 24. Which of the followi
    14·2 answers
  • A: Write an equation that will relate the number of miles driven to the # of gallons of gas.
    6·1 answer
  • What word goes with this definition; Money paid or earned only on the principal
    12·1 answer
  • In ΔTUV, the measure of ∠V=90°, the measure of ∠T=72°, and VT = 6.6 feet. Find the length of TU to the nearest tenth of a foot.
    7·2 answers
  • What are the Lines of symmetry?
    14·1 answer
  • Which kind of triangle is shown
    10·2 answers
  • I need help with this pls:)
    9·1 answer
  • A robot can complete 7 tasks in
    9·1 answer
  • THIS IS DUE IN 5 MINUTES!!!!!!!!!!! I NEEED THIS ASAP! A 13 3/4 -inch candle burns down in 11 hours. If b represents how much of
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!