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Andrej [43]
1 year ago
7

21. To find a baseball pitcher's earned run average (ERA), you can use the formula Ei=9r, in which E represents ERA, i represent

s the number of innings pitched, and r represents the number of eamed runs allowed. Please answer the following and separate your answers by a comma (EX: 10, 11) Solve the equation for E. What is the pitcher's ERA if he allows 5 earned runs in 18 innings pitched?
Mathematics
1 answer:
antoniya [11.8K]1 year ago
7 0

Answer:

E = 2.5

Explanation:

The initial eqauation is E=?r

To solve for E, we need to divide both sides by i as:

\begin{gathered} E\cdot i=9\cdot r \\ \frac{E\cdot i}{i}=\frac{9\cdot r}{i} \\ E=\frac{9\cdot r}{i} \end{gathered}

Now, to calculate the pitcher's ERA, we need to replace r by 5 earned runs and i by 18 innings pitched. Then:

E=\frac{9\cdot5}{18}=2.5

Therefore, the pitcher's ERA is equal to 2.5

9

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monitta

Answer: The area of ABC is 56 m².

Explanation:

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\frac{\text{Area of } \triangle BCP}{\text{Area of } \triangle ABC} =\frac{\frac{1}{2}\times BP\times CH}{\frac{1}{2}\times AB\times CH} =\frac{BP}{AB}= \frac{3}{4}

Since the area of BPC is \frac{3}{4}th part of total area, therefore area of APC is  \frac{1}{4}th part of total area.

The point M is the midpoint of CP, therefore the area of BMP and BMC is equal by midpoint theorem.

\text{Area of } \triangle BMP=\text{Area of } \triangle BMC

21=\text{Area of } \triangle BMC

Area of BPC is,

\text{Area of } \triangle BPC=\text{Area of } \triangle BMP+\text{Area of } \triangle BMC

\text{Area of } \triangle BPC=21+21

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\text{Area of } \triangle APC=\frac{1}{3}\times \text{Area of } \triangle BPC

\text{Area of } \triangle APC=\frac{1}{3}\times 42

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\text{Area of } \triangle ABC=\text{Area of } \triangle APC+\text{Area of } \triangle BPC

\text{Area of } \triangle ABC=14+42=56

Therefore, the area of ABC is 56 m².

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3 years ago
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