Answer:
Step-by-step explanation:
To isolate the term of x from one side of the equation, you must multiply by a polynomial.
<u>You have to solve with parentheses first.</u>
<u>Solve.</u>
x(-5x)=-5x²
3*3x²=9x²
3(-5x)=-15x
3(-10)=-30
<u>Then, rewrite the problem down.</u>
<u>Combine like terms.</u>
<u>Add/subtract the numbers from left to right.</u>
-5x²+9x²=4x²
<u>Solve.</u>
<u>Then rewrite the problem.</u>
- <u>Therefore, the correct answer is 3x³+4x²-25x-30.</u>
I hope this helps! Let me know if you have any questions.
D.68
A squared plus b squared equals c squared and so add the two lengths given and square them which gives you the hypotenuse squared so then find the square root of your result which is 68
answer:
yes, thank you for the points
step-by-step explanation:
- let me know if you have any other questions
- but thank you for the POINTS
Compute the derivative dy/dx using the power, product, and chain rules. Given
x³ + y³ = 11xy
differentiate both sides with respect to x to get
3x² + 3y² dy/dx = 11y + 11x dy/dx
Solve for dy/dx :
(3y² - 11x) dy/dx = 11y - 3x²
dy/dx = (11y - 3x²)/(3y² - 11x)
The tangent line to the curve is horizontal when the slope dy/dx = 0; this happens when
11y - 3x² = 0
or
y = 3/11 x²
(provided that 3y² - 11x ≠ 0)
Substitute y into into the original equation:
x³ + (3/11 x²)³ = 11x (3/11 x²)
x³ + (3/11)³ x⁶ = 3x³
(3/11)³ x⁶ - 2x³ = 0
x³ ((3/11)³ x³ - 2) = 0
One (actually three) of the solutions is x = 0, which corresponds to the origin (0,0). This leaves us with
(3/11)³ x³ - 2 = 0
(3/11 x)³ - 2 = 0
(3/11 x)³ = 2
3/11 x = ³√2
x = (11•³√2)/3
Solving for y gives
y = 3/11 x²
y = 3/11 ((11•³√2)/3)²
y = (11•³√4)/3
So the only other point where the tangent line is horizontal is ((11•³√2)/3, (11•³√4)/3).
