What are the coordinates of vertex J of the pre-image?(14 POINTS. PLS HELP, GEOMETRY)

Mathematics

2 answers:

LUCKY_DIMON [66]3 years ago

6 0

If quadrilateral JKLM was dilated with scale factor 1/2 and center of dilation at origin to form quadrilateral J'K'L'M', then when you dilate quadrilateral J'K'L'M' with scale factor 2 and center of dilation at origin, you obtain quadrilateral JKLM.

The coordinates of quadrilateral J'K'L'M' are:

J'(0,-2), K'(3,2), L'(6,-2) and M'(3,-6).

Then the coordinates of quadrilateral JKLM are:

J(0,-4), K(6,4), L(12,-4) and M(6,-12).

Answer: correct choice is A: J(0,-4).

DaniilM [7]3 years ago

5 0

If we look at where it is now, we would have multiplied the x and y values by 1/2. since we are working backwards, lets multiply by 2 instead...giving us the vertex for the pre-image....

J is now (0, -2) multiply by 2
J was (0, -4)

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. Find the value or values of x in the quadratic equation x2 = 6x – 9. A. x = 9 B. x = 3 C. x = –3, x = 2 D. x = 0, x = 1 Mark f

andrey2020 [161]

Answer:

B. x = 3

Step-by-step explanation:

The equation can be rearranged to ...

x² -6x +9 = 0

(x -3)² = 0 . . . .show as the square it is

x -3 = 0 . . . . . take the square root*

x = 3 . . . . . . . . add 3

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* If the root were non-zero, there would be two of them: ±√( ). That would give rise to two possible values of x. That is not the case here, so there is only one solution.

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In the attached graph, the red curve represents the left side of the equation. The blue line represents the right side. They are equal at the one point where they intersect: (3, 9). That means when x=3, the equation becomes 9=9.