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const2013 [10]
3 years ago
15

A baker uses 5.5 pounds of flour daily How many ounces of flour will he use in two weeks (1lb=160z) *PLZ HELP

Mathematics
2 answers:
bixtya [17]3 years ago
6 0
There are 14 days in two weeks.
5.5 x 2 = 77 lbs.
77 lbs = 1,232 oz.
The baker will use 1,232 oz of flour in two weeks.
LenaWriter [7]3 years ago
6 0
5.5*14= pounds of flour for two weeks = 77 lbs.
77 lbs * 16 oz/lb = 1232 oz.
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(25 POINTS) Find the coordinates of the missing endpoint if E is the midpoint of DF such that F(2,9) and
Natali5045456 [20]

Answer:

(-5, 3)

Step-by-step explanation:

The coordinates of the midpoint are the averages of the endpoints.

-1.5 = (x + 2) / 2

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x = -5

6 = (y + 9) / 2

12 = y + 9

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When f(x) is replaced with<br> f(x)+k, the graph that results is shown below <br> K=__?
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Answer:

k = 6

Step-by-step explanation:

Parent function of the given graph → f(x) = (x - 1)²

If the parent function is shifted 6 units up.

Equation of the translated function will be → g(x) = (x - 1)² + 6

g(x) = f(x) + 6

Therefore, k = 6 will be the answer.

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Whai si (3x+5) (x-2)
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2 years ago
Complete the identity.<br> 1) sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?
Alecsey [184]

Answer:

See Explanation

Step-by-step explanation:

<em>Question like this are better answered if there are list of options; However, I'll simplify as far as the expression can be simplified</em>

Given

sec^4 x + sec^2 x tan^2 x - 2 tan^4 x

Required

Simplify

(sec^2 x)^2 + sec^2 x tan^2 x - 2 (tan^2 x)^2

Represent sec^2x with a

Represent tan^2x with b

The expression becomes

a^2 + ab- 2 b^2

Factorize

a^2 + 2ab -ab- 2 b^2

a(a + 2b) -b(a+ 2 b)

(a -b) (a+ 2 b)

Recall that

a = sec^2x

b = tan^2x

The expression (a -b) (a+ 2 b) becomes

(sec^2x -tan^2x) (sec^2x+ 2 tan^2x)

..............................................................................................................................

In trigonometry

sec^2x =1  +tan^2x

Subtract tan^2x from both sides

sec^2x - tan^2x =1  +tan^2x - tan^2x

sec^2x - tan^2x =1

..............................................................................................................................

Substitute 1 for sec^2x - tan^2x in (sec^2x -tan^2x) (sec^2x+ 2 tan^2x)

(1) (sec^2x+ 2 tan^2x)

Open Bracket

sec^2x+ 2 tan^2x ------------------This is an equivalence

(secx)^2+ 2 (tanx)^2

Solving further;

................................................................................................................................

In trigonometry

secx = \frac{1}{cosx}

tanx = \frac{sinx}{cosx}

Substitute the expressions for secx and tanx

................................................................................................................................

(secx)^2+ 2 (tanx)^2 becomes

(\frac{1}{cosx})^2+ 2 (\frac{sinx}{cosx})^2

Open bracket

\frac{1}{cos^2x}+ 2 (\frac{sin^2x}{cos^2x})

\frac{1}{cos^2x}+ \frac{2sin^2x}{cos^2x}

Add Fraction

\frac{1 + 2sin^2x}{cos^2x} ------------------------ This is another equivalence

................................................................................................................................

In trigonometry

sin^2x + cos^2x= 1

Make sin^2x the subject of formula

sin^2x= 1  - cos^2x

................................................................................................................................

Substitute the expressions for 1  - cos^2x for sin^2x

\frac{1 + 2(1  - cos^2x)}{cos^2x}

Open bracket

\frac{1 + 2  - 2cos^2x}{cos^2x}

\frac{3  - 2cos^2x}{cos^2x} ---------------------- This is another equivalence

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3 years ago
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