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4 years ago

What number must be added to the expression below to complete the square? x^2+x. a.1/4 b.1/2 c.2 d.1

Mathematics

1 answer:

torisob [31]4 years ago

3 0

Option a. 1/4 is the right answer

Step-by-step explanation:

Given expression is:

$x^2+x$

Here

we know that

a = x

In order to find the number which should be added

comparing with the formula

$(a+b)^2 = a^2+2ab+b^2$

$2ab = x\\2.x.b = x\\b=\frac{x}{2x}\\b = \frac{1}{2}$

So, we will add the square of 1/2 which is 1/4

Hence,

Option a. 1/4 is the right answer

Keywords: Expressions, polynomials

Learn more about polynomials at:

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Josefina pain rent for 5 months. She paid a total of $2045. how much did she pay per month?

djverab [1.8K]

Answer:

$409 per month

Step-by-step explanation:

If josefina paid $2045 over a time period of 5 months, then we have to divide how much she paid ($2045) by 5 to find out how much she paid for rent in 1 month.

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3 years ago

natima [27]

Answer:

See explanation

Step-by-step explanation:

Let x be the number of spade shovels, y -the number of flat shovels and z - the number of square showels sold that day.

The store keeps an inventory of 80 shovels, then

x+y+z=80

The store always buy twice as many spade shovels as square, so

x=2z

The total cost of all shovels is

16x+9.60y+12.80z=1,072

a) The system of three equations is

$\left\{\begin{array}{l}x+y+z=80\\ \\x=2z\\ \\16x+9.60y+12.80z=1,072\end{array}\right.$

b) In matrix form this is

$\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}80\\0\\1,072\end{array}\right)$

c) The determinant is

$\left\|\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right\|=0-32+9.60-0+19.20-12.80=-16$

d) Find three determinants:

$\left\|\begin{array}{ccc}80&1&1\\ 0&0&-2\\ 1,072&9.60&12.80\end{array}\right\|=0-2,144+0-0+1,536-0=-608$

$\left\|\begin{array}{ccc}1&80&1\\ 1&0&-2\\ 16&1,072&12.80\end{array}\right\|=0-2,560+1,072-0+2,144-1,024=-368$

$\left\|\begin{array}{ccc}1&1&80\\ 1&0&0\\ 16&9.60&1,072\end{array}\right\|=0+0+768-0-0-1,072=-304$

So,

$x=\dfrac{-608}{-16}=38\\ \\y=\dfrac{-368}{-16}=23\\ \\z=\dfrac{-304}{-16}=19$

e) If the store doubled all prices and inventory, then the new matrix is

$\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 32&19.20&25.60\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}160\\0\\2,144\end{array}\right)$

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Answer:

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Step-by-step explanation:

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