Ok, make sure you put the powers correctly. I know what you mean but someone else may not. So it's step 2. This is because the 4 doesn't mean add a digit.
Answer:

Step-by-step explanation:
<h2>Given that :</h2>
- The radius of a circle is 2.9 in.
<h2>to find :</h2>
- Find the circumference to the nearest tenth.
<h2>formulas used :</h2>
- circumference = 2 × π × r
where,
<h2>explanation :</h2>
⟼ c = 2πr
⟼ c = 2 × 22/7 × 2•9 inches
⟼ c = 2 × 3•14 × 2•9 inches
⟼ c = 6•28 × 2•9 inches
⟼ c = 18•21 inches.
<h2>Round to the nearest tenth :</h2>
⟼ c = 18•21 inches
⟼ c = 20 inches
∴ circle circumference is 20 inches .
Answer:
There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so
.
What is the probability that a line width is greater than 0.62 micrometer?
That is 
So



Z = 2.4 has a pvalue of 0.99180.
This means that P(X \leq 0.62) = 0.99180.
We also have that


There is a 0.82% probability that a line width is greater than 0.62 micrometer.
Luis earns a solid $150 and that doesn't change, now you need to calculate 14% of $6,050.
x=150+(0.14x6050)
150+(847)
997
Luis was paid $997.
3 and 2 should be the only roots