X) = 3 ln(x)
g(x=2) = 3 ln(2)
g(x=4) = 3 ln(4) = 3 ln(22) = 6 ln2
We have two ordered pairs:
(x,3 ln(2)) and (4,6 ln(2))
The average rate of change is the slope (m) of the secant line connecting the two points:
m = (6 ln2 - 3 ln2)/(4-2) = 3ln(2)/2 ≅ 1.04
Answer:I cannot see photo
The equation of a circle is (x-h)²+(y-k)²=r², with h being the x value in the center, k being the y value, and r being the radius. x and y can stay variables, so we can plug numbers in to get (x-0)²+(y-3)²=5²=25=x²+(y-3)²
Answer:
Alan: 200 m/min
Brian: 150 m/min
Step-by-step explanation:
Given : Two cyclists, Alan and Brian, are racing around oval track of length 450m on the same direction simultaneously from the same point. Alan races around the track in 45 seconds before Brian does and overtakes him every 9 minutes.
To find : What are their rates, in meters per minute?
Solution :
Let n represent the number of laps that Alan completes in 9 minutes.
Then n-1 is the number of laps Brian completes.
45 seconds = 3/4 minutes.
The difference in their lap times in minutes per lap is

Solving the equation we get,








Neglecting n=-3
So, n=4
Then Alan's speed in m/min is



Brian completes 3 laps in that 9-minute time, so his rate is


Therefore, Alan: 200 m/min
Brian: 150 m/min