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aleksklad [387]
3 years ago
15

Help plz!! i am stuck and confused plz help!!

Mathematics
1 answer:
fenix001 [56]3 years ago
7 0
525 feet above the ground
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Find the perimeter of the rectangle
kifflom [539]

Answer:

22x + 24

Step-by-step explanation:

7x+9+7x+9+4x+3+4x+3

11x + 18 + 11x + 6

Mark brainliest please!

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2 years ago
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Shawn graphed the points listed below.
Semenov [28]

Answer: A. (4, 4) and (4, 5)

Step-by-step explanation:

The same x value maps onto more than one y value.

6 0
2 years ago
Which of the following is equivalent to
Firlakuza [10]

Answer: it will be D

Step-by-step explanation: if You graph them you will get the same coordinate plates

7 0
2 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 421 gram setting. It is
Anastaziya [24]

Answer:

The p-value is approximately 0.0508

Step-by-step explanation:

The given parameters are;

The expected mass of banana chips bag filled by the machine, μ = 421 gams

The number of bags in the sample of bags filled by the machine, n = 26 bags

The mean mass of the bags in the sample, \overline x = 413 grams

The standard deviation of the mass in the bags, s = 24 grams

The level of significance, α = 0.02

The null hypothesis, H₀; μ = 421 grams

The alternative hypothesis, Hₐ; μ < 421 grams

The test statistic is given as follows;

t=\dfrac{\bar{x}-\mu }{\dfrac{s}{\sqrt{n}}}

We get;

t=\dfrac{413-421 }{\dfrac{24}{\sqrt{26}}} \approx -1.6996731712

The t-value = -1.6996731712

The degrees of freedom df = n - 1 = 26 - 1 = 25

From an online source, we get the critical-t =  2.166587

The p-value is obtained using an online source as p(t ≤  -1.6996731712) = 0.0508

From the p-value table, we get

0.05 < p < 0.1

3 0
2 years ago
Assume the annual day care cost per child is normally distributed with a mean of ​$9000 and a standard deviation of ​$1000. What
Tpy6a [65]

Answer:

65.54% (nearest hundredth)

Step-by-step explanation:

Given:

  • \sf \mu=9000
  • \sf \sigma=1000

\sf X \sim N(\mu, \sigma^2)\implies X \sim N(9000,1000^2)

P(X > 8600) = 1 - P(X ≤ 8600)

                    = 1 - 0.3445782584

                    = 0.6554217416

                    = 65.54%

3 0
2 years ago
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