Answer:
yes
Step-by-step explanation:
Answer:
0, for q ≠ 0 and q ≠ 1
Step-by-step explanation:
Assuming q ≠ 0, you want to find the value of x such that ...
q^x = 1
This is solved using logarithms.
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x·log(q) = log(1) = 0
The zero product rule tells us this will have two solutions:
x = 0
log(q) = 0 ⇒ q = 1
If q is not 0 or 1, then its value is 1 when raised to the 0 power. If q is 1, then its value will be 1 when raised to <em>any</em> power.
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<em>Additional comment</em>
The applicable rule of logarithms is ...
log(a^b) = b·log(a)
Answer:
25
Step by step:
1. prepare the equation
-4 = x/5 - 9
2. add 9 to both sides
-4 = x/5 - 9
+9 +9
5 = x/5
3. multiply both sides by 5
5 = x/5
(5) (5)
25 = x
4. x=25
Hope this helps
