Answer:
1. The network address for 172.22.49.252/17 is 172.22.0.0/17.
2. The last valid assignable host address of 172.22.4.129/26 is 172.22.4.190.
3. The first and last host address of 192.167.25.25/16 is 192.167.0.1 and 192.167.255.254.
4. The broadcast address of 10.75.96.0/20 is 10.75.111.255
Explanation:
Subnetting in networking is the process of managing the use of host addresses and subnet masks of a network IP address. For example, the IP address "172.22.49.252/17" is a class B address that receives an extra bit from the third octet which changes its subnet-mask from "255.255.0.0" to "255.255.128.0". with this, only 32766 IP addresses are used, with the network address of "172.22.0.0/17".
Answer:
The answer is "True".
Explanation:
Industry demands documentation enables developers to monitor the system's range and protects users claims, that somehow the new system will not accomplish their business goals.
- The main goal of this report is to offer everyone to be transparent, about what should be accomplished and when.
- It is the new business plan, that should be outlined in detail, that's why the given statement is true.
The answer is (a.) DOS
DOS stands for Disk Operating System. MS-DOS is the operating system which has a command interface similar to the command prompt of Windows 7 and Windows 8. Among the options, DOS is the only OS which is has a command line interface. Others have graphics.
The answer to this question is B
Please Help! Unit 6: Lesson 1 - Coding Activity 2
Instructions: Hemachandra numbers (more commonly known as Fibonacci numbers) are found by starting with two numbers then finding the next number by adding the previous two numbers together. The most common starting numbers are 0 and 1 giving the numbers 0, 1, 1, 2, 3, 5...
The main method from this class contains code which is intended to fill an array of length 10 with these Hemachandra numbers, then print the value of the number in the array at the index entered by the user. For example if the user inputs 3 then the program should output 2, while if the user inputs 6 then the program should output 8. Debug this code so it works as intended.
The Code Given:
import java.util.Scanner;
public class U6_L1_Activity_Two{
public static void main(String[] args){
int[h] = new int[10];
0 = h[0];
1 = h[1];
h[2] = h[0] + h[1];
h[3] = h[1] + h[2];
h[4] = h[2] + h[3];
h[5] = h[3] + h[4];
h[6] = h[4] + h[5];
h[7] = h[5] + h[6];
h[8] = h[6] + h[7]
h[9] = h[7] + h[8];
h[10] = h[8] + h[9];
Scanner scan = new Scanner(System.in);
int i = scan.nextInt();
if (i >= 0 && i < 10)
System.out.println(h(i));
}
}
