Answer:
x = 3
Step-by-step explanation:
Given in the question an equation,

Step 1

so,

Step 2
cancel 2 on both sides of the equation

Step 3


Step 4

Step 5

Step 6
x/3 = 1
x = 3(1)
x = 3
Given:
The function, f(x) = -2x^2 + x + 5
Quadratic equation: 0 = -2x^2 + x +5
where a = -2
b = 1
c = 5
The discriminate b^2 - 4ac = 41
To solve for the zeros of the quadratic function, use this formula:
x = ( -b +-√ (b^2 - 4ac) ) / 2a
x = ( 1 + √41 ) / 4 or 1.85
x = ( 1 - √41 ) / 4 or -1.35
Therefore, the zeros of the quadratic equation are 1.85 and -1.35.
Answer:
hi
Step-by-step explanation:
but that was no a question but thanks
A − 3b = 16
a = b − 2
b - 2 - 3b = 16
2b = - 18
b = - 9
a = - 9 - 2
a = - 11
(-11,-9)
Answer:
40.3
Step-by-step explanation:
Use pythagoras theorem, a^2 + b^2 = c^2
400 + 1225 = 1625
sqrt of 1625 = approx 40.3