Answer:
$9.3 million
Step-by-step explanation:
Given that the company profit increases by 9% yearly from 2005.
Using the exponential growth formula;
A = P(1+r)^(t) .....1
Where;
A = final amount/value of profit
P = initial amount/value = $6.6 million
r = growth rate yearly = 9% = 0.09
t = time of growth in years = 2009 - 2005 = 4 years
Substituting the values;
A = 6.6(1+0.09)^(4)
A = 6.6(1.09)^(4)
A = 9.3164386 million
A = $9.3 million
The companies profit in the year 2009 to the nearest 10th of $1 million is $9.3 million
Answer:
$10.15
Step-by-step explanation:
0.74*6=4.44
4.44+5.71
Can I get the brainliest
Answer:
impossible
Step-by-step explanation:
There is no expression to plug x and y into
Question 1 the answer is C.
The point-slope form of the equation for a line is good for this. It tells you the line with slope m through point (h, k) has equation
... y -k = m(x -h)
For your point and slope, an equation of the line is
... y -1 = -5(x -9)
