Answer:
none of the above
Step-by-step explanation:
You can try the points in the equations (none works in any equation), or you can plot the points and lines (see attached). <em>You will not find any of the offered answer choices goes through the given points</em>.
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You can start with the 2-point form of the equation of a line. For points (x1, y1) and (x2, y2) that equation is ...
y = (y2 -y1)/(x2 -x1)·(x -x1) +y1
Filling in the given points, we get ...
y = (3 -1)/(2 -4)·(x -4) +1
y = 2/(-2)(x -4) +1 . . . . . simplify a bit
y = -x +4 +1 . . . . . . . . . simplify more
y = -x +5 . . . . . . . . . . . slope-intercept form
4mins---->12 cars
6mins---->(6*12/4)=18
4mins---->12
5mins---->(5*12/4)=15
And so on
<u>Given</u><u> info</u><u>:</u><u>-</u> In triangle (∆)ABC , in which ∠A = 2x, ∠B = x+15° and ∠C = 2x + 10°. Then find the value of x , also find the measure of each angles of a triangle.
<u>Explanation</u><u>:</u><u>-</u>
Let the angles be 2x, x+15 and 2x+10 respectively.
∵ Sum of the three angles of a triangle is 180°
∴ ∠A + ∠B + ∠C = 180° [Sum of ∠s of a ∆=180°]
→2x + x+15 + 2x+10 = 180°
→ 2x + x + 2x + 15 + 10 = 180°
→ 3x + 2x + 15 + 10 = 180°
→ 5x + 15 + 10 = 180°
→ 5x + 25 = 180°
→ 5x = 180°-25
→ 5x = 155°
→ x = 155°÷5 = 155/5 = 31.
Now, finding the measure of each angles of a ∆ABC by putting the original value of “x”.
∴ ∠A = 2x = 2(31) = 62°
∠B = x+15 = 31 + 15 = 46°
∠C = 2x + 10 = 2(31) + 10 = 62 + 10 = 72°.
Mean (Average) 48
Median 47.5
Range 66
Mode 72, appeared 2 times
Geometric Mean 41.680398411848
Largest 81
Smallest 15
Sum 480
Count 10
Answer:
One solution: (2.5,0)
Step-by-step explanation:
We can use substitution for the solution. Substitute y=2x-5 to -8x-4y=-20 so that you end up with -8x-8x+20=-20. Next you want to add like terms which will be -16x+20=-20, next you want isolate x by subtracting 20 from both sides and leaves you with -16x=-40. Divide -16 on both sides to fully isolate x and will leave you with x=2.5. Now substiture in 2.5 for x in y=2x-5 to get y=2(2.5)-5 which will then lead to y=0.
