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noname [10]
3 years ago
13

Jay Olshansky from the University of Chicago was quoted in Chance News as arguing that for the average life expectancy to reach

100, 18% of people would have to live to 120. What standard deviation is he assuming for this statement to make sense? Assume a normal distribution.Group of answer choices35.024.425.221.7
Mathematics
1 answer:
Alex17521 [72]3 years ago
5 0

Answer: 35

Step-by-step explanation:

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Three coins are tossed in the air, one at a time. What is the probability that the third coin will be heads?
marishachu [46]

Answer:

1/2

Step-by-step explanation:

We only care about the third coin

we could get heads or tails on the third flip

P (third coin will be heads) = outcome heads / total

                                            =1/2

8 0
3 years ago
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Write the definition of a function printarray, which has two parameters . the first parameter is an array of integers and the se
Lady bird [3.3K]
Using pseudocode:

printArray(arr[], integers)
      DECLARE integers
      integers = SizeOf(arr)
      FOR i = 1 to integers // loop from 1 to the number of elements in arr[]
            print(i)
            print('')
            i = i + 1
      ENDFOR
END
7 0
3 years ago
Based on the table, which best predicts the end behavior of the graph of f(x)?
Yuki888 [10]

Answer: A. As x → ∞, f(x) → ∞, and as  x → –∞, f(x) → ∞.

6 0
3 years ago
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A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.
AVprozaik [17]

Answer:

X \sim N(61,14)  

Where \mu=61 and \sigma=14

Since the distribution for X is normal then the distribution for the sample mean  is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = 61

\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715

So then is appropiate use the normal distribution to find the probabilities for \bar X

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  The letter \phi(b) is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: \phi(b)=P(z

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(61,14)  

Where \mu=61 and \sigma=14

Since the distribution for X is normal then the distribution for the sample mean \bar X is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = 61

\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715

So then is appropiate use the normal distribution to find the probabilities for \bar X

8 0
3 years ago
Write this number in scientific notation 0.000000358​
Fittoniya [83]

Step-by-step explanation:

0.000000358 written as scientific notation is

3.58 \times  {10}^{ - 7}

8 0
3 years ago
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