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Zielflug [23.3K]
3 years ago
8

Describe a sequence of translations, rotations, and reflections that takes Polygon P to Polygon Q.

Mathematics
1 answer:
MaRussiya [10]3 years ago
6 0

Answer:

TRAIN TRACKS!!!!

Step-by-step explanation:

on edge

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C. g(x) = x^2 + 3

Step-by-step explanation:

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Pat needs 14 sticks of pepperoni to make 28 pizzas. How many sticks of pepperoni are needed to make 36 pizzas?
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Answer:

18

Step-by-step explanation:

It is 18 because 14 x 2 equal 28 so that would mean you need one stick to make 2 pizzas. Then you divide 36 by 2 and get 18

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An area of land has 512 acres. Each acre has 54 blades of
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27,648 blades of grass

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6 0
3 years ago
B is between A and C, AB = 13.7 and BC = 8.3. Find AC. AC = 17 AC = 22 AC = 20 AC = 19
Rom4ik [11]
13.7 + 8.7 = 22
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3 0
3 years ago
Read 2 more answers
g On a certain daily flight, Air Northeast has a policy of booking as many as 22 people on an airplane that can seat only 19. Pa
Fed [463]

Answer:

55.82% probability that there will not be enough seats available for all booked passengers.

Step-by-step explanation:

For each booked passenger, there are only two possible outcomes. Either they arrive for the flight, or they do not arrive. The probability of a booked passenger arriving is independent of other booked passengers. So we used the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The airline books 22 people on a flight

This means that n = 22

Past studies have revealed that only 89% of the booked passengers actually arrive for the flight.

This means that p = 0.89

Find the probability that there will not be enough seats available for all booked passengers.

The airplane seats 19, so this is the probability of more than 19 passengers arriving.

P(X > 19) = P(X = 20) + P(X = 21) + P(X = 22)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 20) = C_{22,20}.(0.89)^{20}.(0.11)^{2} = 0.2718

P(X = 21) = C_{22,21}.(0.89)^{21}.(0.11)^{1} = 0.2094

P(X = 22) = C_{22,22}.(0.89)^{22}.(0.11)^{0} = 0.0770

P(X > 19) = P(X = 20) + P(X = 21) + P(X = 22) = 0.2718 + 0.2094 + 0.0770 = 0.5582

55.82% probability that there will not be enough seats available for all booked passengers.

7 0
3 years ago
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