Upper Tolerance
Remark
The 11/16 is the only thing that will be affected. The three won't go up or down when we add 1/64 so we should just work with the 11/16. We need only add 11/16 and 1/64 together to see what the upper range is. Later on we can add 3 into the mix.
Solution
<u>Upper Limit</u>
Now change the 11/16 into 64. Multiply numerator and denominator or 11/16 by 4
Which results in
With a final result for the fractions of 45/64
So the upper tolerance = 3 45/64
<u>Lower Tolerance</u>
Just follow the same steps as you did for the upper tolerance except you subtract 1/64 like this.
Your answer should be 3 and 43/64
If you're using a few larger intervals, then your histogram looks more stocky. If you imagine drawing one, it's because you're adding more values into the same category which can make the difference between two intervals much more noticeable. If you're using smaller intervals, however, you can much more accurately assess the difference between two different intervals. For that reason, the transition between one and another interval would look much more 'fluid'.
Answer:
f(x) -> 2 as x -> -∞ and f(x) -> ∞ as x -> ∞
Step-by-step explanation:
f(x) -> 2 as x -> -∞ and f(x) -> ∞ as x -> ∞
*this is because the graph shows that the y value cannot pass by 2 as the x value constantly decreases and as x is increasing, there is just an arrow showing that the graph is constantly going up and therefore going to ∞
The answer would be 115°, the sum of interior angles in a kite is always 360° so if 41° and 89° equal 130° subtract 130° from 360° and that gives you 230° divide that by two for each side of the kite missing and you get 115°
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