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3 years ago

I am not sure about any of my answers and I don’t know how to find the range for question b or the slope for question c.

Mathematics

1 answer:

myrzilka [38]3 years ago

7 0

Answer:

a) is correct

b) y = -a(x - 2.5)² + h

(5.5,0)

0 = -a(5.5-2.5)² + h

h = 9a

a = h/9

48 = -a(0-2.5)² + h

h = 48 + 6.25a

h = 48 + 6.25(h/9)

h = 157.0909090681

Range: [0,157]

c) (80-144)/(4.5-3)

= -42⅔ or -42.67

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Can you answer this? <br> factorise 6p + 24q

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Answer:

6(p+4q)

Step-by-step explanation:

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3 years ago

Which factorization is equivalent to this expression?

grigory [225]

Answer:

$10(3x+7)$

Step-by-step explanation:

we have the expression:

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To factor this expression we need to indentify the components that are common in both terms.

At first glance there is nothing in common, but we can notice that 30 and 70 are multiples of 10, that is:

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so we can substitute this into the expression:

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2 years ago

A plane takes off from an airport and flies at a speed of 400km/h on a course of 120° for 2 hours. the plane then changes its co

butalik [34]

Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

$\displaystyle \vec{v}=\frac{\vec{x}}{t}$

Where $\vec x$ is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

$\displaystyle \vec{x}=\vec{v}.t$

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

$\displaystyle \vec{v_1}=$

$\displaystyle \vec{v_1}=\ km/h$

The displacement of the plane in 2 hours is

$\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)$

$\displaystyle \vec{x_1}=km$

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

$\displaystyle \vec{v_2}=$

$\displaystyle \vec{v_2}=km/h$

The displacement in 1 hour is

$\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)$

$\displaystyle \vec{x_2}=km$

The total displacement is the vector sum of both

$\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+$

$\displaystyle \vec{x_t}=km$

$\displaystyle \vec{x_t}=$

The distance from the airport is the module of the displacement:

$\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}$

$\displaystyle |\vec{x_t}|=894.43\ km$

8 0

3 years ago

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puteri [66]

Answer: i think it is... x = -19

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3 years ago

Given the diagram below find x, and the measure of

Sophie [7]

Answer:

8, 40 , 50

Step-by-step explanation:

the measure of A is 90°

so 5x + 7x - 6 = 90

now.. to find the x

5x + 7x - 6 = 90

5x + 7x = 90 + 6

12x = 96

x = 96/12

x = 8

so the measure of angle A1 is (5*8) = 40

the measure of angle A2 is (7*8-6) = 50

finaly the angle A is (50+40) = 90

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3 years ago