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Tatiana [17]
2 years ago
15

Which ratios of side lengths are equal to tan (a) ?

Mathematics
2 answers:
Eddi Din [679]2 years ago
4 0

Answer:

tan(\alpha)=\frac{opposite}{adjacent}

Step-by-step explanation:

tan(\alpha)=\frac{opposite}{adjacent}

Effectus [21]2 years ago
3 0

Answer:

tan = opposite ÷ adjecent

opposite is the side perpendicular( at 90 degrees to the base or adjacent side.

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the size of the second application is 3.45 MB less than he first application. What is the size of the second application
mr_godi [17]

The size of the second application given the size of the first application and the expression ( x - 3.45 mb) for the size of the second application is 293.55 MB.

<h3>Equation</h3>

Let

  • Size of the first application = x

  • Size of the second application= x - 3.45 mb

For instance,

if the size of the first application is 297 MB

Size of the second application= x - 3.45 mb

= 297 MB - 3.45 MB

= 293.55 MB

Therefore, the size of the second application given the size of the first application and the expression for the size of the second application is 293.55 MB

Learn more about equation:

brainly.com/question/2972832

#SPJ1

6 0
2 years ago
Please answer quickly its a test and i need to get a good grade on it, will give brainliest
Helga [31]

I think the answer is A because it I'm right it did double the size.

3 0
3 years ago
I’m confused on this one
dedylja [7]

It's a parallelogram so if one angle is 90 degrees they all will be because of transverse angles and all that good stuff.


So we're given the diagonal of a rectangle and one side and we're asked to find the other. The diagonal of a rectangle is the hypotenuse of the right triangle whose legs are the sides of the rectangle. So this is a Pythagorean Theorem question in disguise:


AB^2 + AD^2 = BD^2


AD^2 = BD^2 - AB^2


AD = \sqrt{ BD^2 - AB^2 }


AD = \sqrt{149^2 - 51^2} = \sqrt{19400} = 140


Answer: 140 cm


I don't recall seeing this Pythagorean Triple before.





3 0
3 years ago
A rope pulling a sled is sloped at 15° upward at the point of contact. The tension in the rope is 50.0 N. What is the horizontal
gizmo_the_mogwai [7]

Answer:

The horizontal component of the force is 48 N.

Step-by-step explanation:

The angle that the rope makes with with the horizontal is 15°, that means, the horizontal component of the force F_H is

cos(15^o)=\frac{F_H}{50N}

\boxed{ F_H=50N*cos(15^o)=48N}

4 0
3 years ago
Is the following shape a square? How do you know
swat32
Yes, they all have 4 corners.
3 0
2 years ago
Read 2 more answers
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