Answer: This is life science right? If it is the answer is the microscope
Explanation:
Cross between "Homozygous Dominant" & "Homozygous recessive" would result in offspring of phenotype 1:1:1:1. When linkage is not occurs!
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It makes sure they are in perfect condition for it to go through the cell cycle easier
Answer:
1/4
Explanation:
Cystic fibrosis is a recessive disorder and therefore, is expressed only in homozygous recessive genotype. Let's assume that the allele "c" is responsible for the disease in the homozygous state. Since the couple already has a child with cystic fibrosis (cc), they both are heterozygous carriers for the disease.
The genotype of male and female each is "Cc". A cross between Cc x Cc gives progeny in the following phenotype ratio=1/4 diseased: 1/2 normal carriers: 1/4 normal. Therefore, the probability of getting a diseased child for them is 1/4.