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3 years ago

14

How you substract 7 from 52

2 answers:

ioda3 years ago

6 0

52-7 which equals 45

lesya692 [45]3 years ago

5 0

DO 52
- 7
which is 45

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3. A piece of white oak has a densityof 0.77 g/cm and a mass of 100 g,what would be the volume of thesample? PLEASE HELP!

Nezavi [6.7K]

$\text{Volume}=129.87cm^3$

Explanation

Step 1

the density of an object is given by:

$\text{density}=\text{ }\frac{mass}{\text{volume}}$

Step 2

let

$\begin{gathered} \text{density}=0.77\frac{g}{cm^3} \\ \text{mass}=\text{ 100 g} \\ \end{gathered}$

Step 3

replace,

$\begin{gathered} \text{density}=\text{ }\frac{mass}{\text{volume}} \\ 0.77\frac{g}{cm^3}=\frac{100g}{\text{volume}} \\ \text{volume}\cdot0.77\frac{g}{cm^3}=\text{1}00\text{ g} \\ \\ \text{Volume}=\frac{100\text{ g}}{0.77\frac{g}{cm^3}} \\ \text{Volume}=129.87cm^3 \end{gathered}$

I hope this helps you

5 0

1 year ago

Who try to play quizizz with me

algol [13]

Answer: no thanks im good

5 0

3 years ago

Read 2 more answers

Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method

antoniya [11.8K]

Answer:

a

The estimate is $- 0.0265\le K \le 0.0465$

b

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is $n_1 = 400$

The number of faulty breaks of method A is $X_1 = 32$

The number of microchips broken in method B is $n_2 = 400$

The number of faulty breaks of method A is $X_2 = 32$

The proportion of the faulty breaks to the total breaks in method A is

$p_1 = \frac{32}{400}$

$p_1 = 0.08$

The proportion of the faulty to the total breaks in method B is

$p_2 = \frac{28}{400}$

$p_2 = 0.07$

For this estimation the standard error is

$SE = \sqrt{ \frac{p_1 (1 - p_1)}{n_1} + \frac{p_2 (1- p_2 )}{n_2} } }$

substituting values

$SE = \sqrt{ \frac{0.08 (1 - 0.08)}{400} + \frac{0.07 (1- 0.07 )}{400} } }$

$SE = 0.0186$

The z-values of confidence coefficient of 0.95 from the z-table is

$z_{0.95} = 1.96$

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

$K = [p_1 - p_2 ] \pm z_{0.95} * SE$

substituting values

$K = [0.08 - 0.07 ] \pm 1.96 *0.0186$

$K = - 0.0265 \ or \ K = 0.0465$

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is

$- 0.0265\le K \le 0.0465$

3 0

3 years ago

What are the base and the exponent in10 6

SIZIF [17.4K]

I'm assuming it's 10^6, so 10 would be the base, and 6 would be the exponent.

6 0

3 years ago

Read 2 more answers

Tax returns filed manually have a 20% chance of containing errors, while tax returns filed electronically have a 0.05% chance of

suter [353]

Answer:

B) 538, 650

Step-by-step explanation:

Given:

Errors on tax returns filed manually = 20%

Errors on tax returns filed electronically = 0.05%

Tax return filled in each way = 2.7 million

Manual filing:

2,700,000 x 20% = 2,700,000*0.2 = 540,000

Electronic filing:

2,700,000 x 0.05% = 2, 700,000*0.0005 = 1,350

Error difference = 540,000 - 1,350 = 538,650

There will be 538,650 more erroneous tax returns filed manually than there are filed electronically.

Thank you.

3 0

3 years ago

Read 2 more answers