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3 years ago

For the figure shown on the right find M 1

Mathematics

2 answers:

katrin2010 [14]3 years ago

3 0

I think that’s a brand of tape beacuse there’s duck tape, scotch tape, paint tape, washie tape etc

Hope this helps:)

shtirl [24]3 years ago

3 0

Explanation: The triangle exterior angle theorem states that the measure of each exterior angle of a triangle equals the sum of the measures of its two remote interior angles.

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Bonjour , je n'arrive pas a faire ces calcules quelqu'un pourrais m'aidez Voici les calculs : 1 sur 4 - 3 sur 4 et calculer un p

Gre4nikov [31]

Bonjour!
90% de 2300=2070
112% de 80= 100% de 80 + 12% de 80 = 89.6km/h
:)

3 0

3 years ago

The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)

Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics = $\frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } }$ follows $t_n_- _1$ .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores and D = difference between both

So, $\mu_A$ = Population mean for the math scores

$\mu_B$ = Population mean for the writing scores

Let $\mu_D$ = Difference between the population mean for the math scores and the population mean for the writing scores.

Null Hypothesis, $H_0$ : $\mu_A = \mu_B$ or $\mu_D$ = 0

Alternate Hypothesis, $H_1$ : $\mu_A \neq \mu_B$ or $\mu_D \neq$ 0

Hence, Test Statistics used here will be;

$\frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } }$ follows $t_n_- _1$ where, Dbar = Bbar - Abar

$s_D$ = $\sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}$

n = 12

Student Math scores (A) Writing scores (B) D = B - A

1 540 474 -66

2 432 380 -52

3 528 463 -65

4 574 612 38

5 448 420 -28

6 502 526 24

7 480 430 -50

8 499 459 -40

9 610 615 5

10 572 541 -31

11 390 335 -55

12 593 613 20

Now Dbar = Bbar - Abar = 489 - 514 = -25

Bbar = $\frac{\sum B_i}{n}$ = $\frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}$ = 489

Abar = $\frac{\sum A_i}{n}$ = $\frac{540+432+528+574+448+502+480+499+610+572+390+593}{12}$ = 514

∑ $D_i^{2}$ = 22600 and $s_D$ = $\sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}$ = $\sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} }$ = 37.05

So, Test statistics = $\frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } }$ follows $t_n_- _1$

= $\frac{-25 - 0}{\frac{37.05}{\sqrt{12} } }$ follows $t_1_1$ = -2.34

Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0

3 years ago

I need help with Question 14 . I need to submit it by monday... Pls help

GaryK [48]

Answer:

Distance between A and B is 5400 meters

Step-by-step explanation:

Consider "D" the letter to identify distance between A and B

Let's use "t" to identify the time of the first encounter (Devi and Kumar), and create an equation that states that the distance covered by Devi (at 100 m/min) in time "t", is equal to the total distance D minus what Kumar has covered at his speed (80 m/min) in that same time:

Recall that distance equals the speed times the time:

distance= speed * time

First encounter:

100 * t = D - 80 * t

180 * t = D Equation (1)

Not, 6 minutes later (at time t+6) , Devi and Li Ting meet .

Then for this encounter the distance covered by Devi equals total distance d minus the distance covered by Li Ting:

100 *(t+6) = D - 75 * (t+6)

100 t + 600 = D - 75 t - 450

175 T + 150 = D Equation (2)

Now, let's equal equation (1) to equation (2), since D should be the same:

180 t = 175 t + 150

5 t = 150

t = 30

Then the time t (first encounter) is 30 minutes. Knowing this, we can use either equation to find D:

From Equation (1) for example: D = 180 * t = 180 * 30 = 5400 meters

5 0

3 years ago

What time is it when the hour hand is a little past the 3 and the minite hand is pointing to the 3?

Lisa [10]

3:15 because its till 3 o'clock and in each 1 theres 5 inside so 3x 5 = 15.
Thats how I got the answer 3:15 o'clock.

Hoped it help! :D

4 0

3 years ago

Read 2 more answers

Which is a good comparison of the estimated sum and the actual sum of 7 10/12+2 11/12

notka56 [123]

The answer will be 9 1/12 because if you add them up you get 11/12. So the mixed number would be 9 1/12

5 0

3 years ago