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3 years ago

9

I need the anwser and the fractions

1 answer:

alexandr1967 [171]3 years ago

7 0

Answer:

5.5/3 - 3/1 = 2.5/3

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PLZ HELP NNOOOOOOOWW!! 15 points!!

motikmotik

The midpoint of the line having the endpoints $(x_1,y_1)$ and $(x_2,y_2)$ is $(\frac{x_{1}+_x_{2}}{2}, \frac{y_{1}+_y_{2}}{2})$
basically average them

so given that the line has the endpoints of (-3,7) and (9,-2)
x₁=-3
y₁=7
x₂=9
y₂=-2

so the midpoint can be found by doing
$(\frac{-3+9}{2}, \frac{7+(-2)}{2})=$
$(\frac{6}{2}, \frac{7-2}{2})=$
$(3, \frac{5}{2})$

the midpoint is $(3,\frac{5}{2})$

4 0

3 years ago

A tour director collected $258 for 13 tour packages tour packages a cost $18 into a package requires $22 how many of each tour p

Lena [83]

Answer:

Step-by-step explanation:

X+Y = 13

$18 + $22 = $258

OR

18X+22Y=258

18X + 22(13 - X) = 258

18X + 286 - 22X = 258

286 - 4X = 258

-4X= 258 - 286

-4X = -28

X= 7

Y=6

7 of the X tour packages & 6 of the Y tour packages

4 0

3 years ago

PLEASE HELP:))))))) 15points

Zielflug [23.3K]

Answer:7 cm

Step-by-step explanation: you know everything except the radius. Use this equation to help you: 44=2*pi*radius

Divide 44 by 2pi. Then u have your radius which is 7

7 0

3 years ago

44cm is rounded to the nearest whole cm. whats the minimum length it could have been

baherus [9]

43.5 because if it were anything below that it would've been rounded down to 43 instead of up to 44.

4 0

3 years ago

Use logarithmic differentiation to find the derivative of the function.y = x^8 sin(x)

givi [52]

$Answer: \frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})$

Step-by-step explanation:

Since we have given that

$y=x^{8sinx}$

By using logarithmic on both sides we get,

$log y= 8 sinx. logx$

(∵ $log(a^m)=m.loga$ )

Now, differentiating on both sides ,we get,

$\frac{1}{y}.\frac{\partial y}{\partial x}=8(\frac{\partial sinx}{\partial x}.logx+sinx \frac{\partial logx}{\partial x})$

$\\\frac{1}{y}\frac{\partial y}{\partial x}=8(cosx.logx+sinx.\frac{1}{x})$

$\\\frac{\partial y}{\partial y}=8y(cosx.logx+\frac{sinx}{x})\\\\\frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})$

6 0

3 years ago