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Dmitry [639]
3 years ago
10

Suppose 53.0 ml of 0.320 m koh is mixed with 28.0 ml of 0.250 m hno3. what is the concentration of oh- ions after the reaction g

oes to completion? express your answer in mol/l
Chemistry
1 answer:
zheka24 [161]3 years ago
4 0
Given:

Volume of KOH = 53.0 mL
Concentration of KOH = 0.320 M
Volume of HNO3 = 28.0 mL
Concentration of HNO3 = 0.250 M

Balanced Equation:

KOH + HNO3 ===> KNO3 + H2O

0.320   0.250        0              0

H2O ===> H+   +   OH-

Solve for the concentration of OH-
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If 5.4 moles of Fe react with 4.7 moles of O2, what is the maximum amount of Fe2O3 (in moles) that can be produced? What is the
DIA [1.3K]

Answer:

2.7 moles of Fe₂O₃ is the maximum amount that can be produced. Iron is the limiting reactant.

Explanation:

The balanced reaction is:

4 Fe + 3 O₂ → 2 Fe₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Fe: 4 moles
  • O₂: 3 moles
  • Fe₂O3: 2 moles

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

You can use a simple rule of three as follows: if by stoichiometry 4 moles of Fe reacts with 3 moles of O₂, how much moles of Fe will be needed if 4.7 moles of O₂ react?

moles of Fe =\frac{4. moles of Fe*4.7 moles of O_{2}}{3 moles of O_{2} }

moles of O₂= 6.27

But 6.27 moles of Fe are not available, 5.4 moles are available. Since you have less moles than you need to react with 4.7 moles of O₂, iron Fe will be the limiting reagent.

So you can use a simple rule of three as follows: if by stoichiometry 4 moles of Fe produce 2 moles of Fe₂O₃, how many moles of Fe₂O₃ will be produced if 5.4 moles of Fe react?

moles of Fe_{2}O_{3}=\frac{5.4 moles of Fe*2 moles of Fe_{2} O_{3} }{4 moles of Fe}

moles of Fe₂O₃= 2.7 moles

Then:

<u><em>2.7 moles of Fe₂O₃ is the maximum amount that can be produced. Iron is the limiting reactant.</em></u>

4 0
3 years ago
An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 115.00 u and 117.00 u, with natural abun
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(115.00)(0.25)+(117.00)(0.75)=\boxed{116.50 \text{ u}}

3 0
2 years ago
Which factors can influence the length of time it takes for a half-life to occur?
vovikov84 [41]

Answer:

the radioactive half-life of an atom can depend on how it is bonded to other atoms. by changing the neighboring atoms that are bonded to a radioactive isotope, we can change its half-life.

Explanation:

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3 years ago
What are things that amorphous and crystalline have in common?
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Six brick land llwnswel
5 0
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Be sure to answer all parts. Carbon disulfide, a poisonous, flammable liquid, is an excellent solvent for phosphorus, sulfur, an
sveticcg [70]

Explanation:

Experiment Initial [CS2] (mol/L) Initial Rate (mol/L·s)

1 0.100 2.7 × 10−7

2 0.080 2.2 × 10−7

3 0.055 1.5 × 10−7

4 0.044 1.2 × 10−7

a) Choose the rate law for the decomposition of CS2.

Comparing equations 1 and 3, reducing the initial concentration by almost half (from 0.100 to 0.055) leads too the rate of reaction to be reduced by almost half (from 2.7 × 10−7 to 1.5 × 10−7).

This signifies that the reaction is a first order reaction.

Rate = k [CS2]

(b) Calculate the average value of the rate constant.

Taking equation 1.

Rate = k [CS2]

k = Rate / [CS2]

k = 0.100 / (2.7 × 10−7)  = 0.037 x 10^8 = 3.7 x 10^6s-1

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3 years ago
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