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3 years ago

7

You and your mate both have typical pigmentation and have a child with albinism. Which of the following Punnett squares represen

ts the cross between you and your mate?
A

B

C

D

1 answer:

Reika [66]3 years ago

7 0

I would like to help you, but you are not showing the options. just their letter.

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3. A tea kettle holds about<br> of water.<br> 2 mL<br> 200 mL<br> 2L<br> 200 L

cluponka [151]

A tea kettle holds on average about 1.7-2 Liters of water. So the answer should be 2 Liters

3 0

4 years ago

Read 2 more answers

What is a saturated solution that cannot dissolve any more solute because it is too concentrated?

Aleksandr-060686 [28]

Answer:

concentrated B ...............

7 0

3 years ago

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Which of the following is considered applied research?

dexar [7]

The correct answer is option B.

Research focused on how to cure cancer is an example of applied research.

The examples of basic research are :

A.) Research focused on how the human brain works

C.) Research focused on detecting life on other planets

D.) Research focused on human behavior

Applied research targets to solve specific human problems that have commercial value in the present day. Basic research is about understanding the fundamentals of science and nature, and it is essential to laying down the foundation of applied research.

3 0

3 years ago

Aside from the reaction proceeding in the test tube, there is a second reaction that occurs when you hold the lit splint inside

tino4ka555 [31]

Answer:

c

Explanation:

4 0

4 years ago

At a wastewater treatment plant, FeCl3(s) is added to remove excess phosphate from the effluent. Assume the following reactions

RoseWind [281]

Answer : The concentration of $Fe^{3+}$ needed is, $2.37\times 10^4M$

Explanation :

First we have to calculate the mole of phosphate.

As we are given that, 1 mg P/L that means, 1 mg of phosphate present in 1 L of solution.

$\text{Moles of phosphate}=\frac{\text{Mass of phosphate}}{\text{Molar mass of phosphate}}$

Molar mass of phosphate = 94.97 g/mole

$\text{Moles of phosphate}=\frac{1mg}{94.97g/mol}=\frac{0.001g}{94.97g/mol}=1.053\times 10^{-5}mol$

Now we have to calculate the concentration of phosphate.

$\text{Concentration of phosphate}=\frac{\text{Moles of phosphate}}{\text{Volume of solution}}$

$\text{Concentration of phosphate}=\frac{1.053\times 10^{-5}mol}{1L}=1.053\times 10^{-5}mol/L$

Now we have to calculate the concentration of $Fe^{3+}$ .

The second equilibrium reaction is,

$FePO_4\rightleftharpoons Fe^{3+}+PO_4^{3-}$

The solubility constant expression for this reaction is:

$K_{sp}=[Fe^{3+}][PO_4^{3-}]$

Given: $K_{sp}=\frac{1}{4}$

$\frac{1}{4}=[Fe^{3+}]\times 1.053\times 10^{-5}mol/L$

$[Fe^{3+}]=2.37\times 10^4M$

Thus, the concentration of $Fe^{3+}$ needed is, $2.37\times 10^4M$

8 0

4 years ago