Several pieces of equipment can do this, including the Bunsen burner, laboratory oven, hot plate and incubator.
Answer:
Explanation:
Use Dalton's law and the vapor pressure of water at 23.0 o C to correct the pressure to units of atmoshperes.
PT = Poxygen +Pwater
At 23.0 o C the vapor pressure of water is 21.1 mmHg. (This can be found on a vapor pressure table.)
762 mmHg = Poxygen + 21.1 mmHg
Poxygen = 762 mmHg - 21.1 mmHg
Poxygen =741 mmHg
Convert the corrected pressure to atmospheres.
(741 mmHg) (1 atm / 760 mmHg) = 0.975 atm
Use the ideal gas law to find out how many moles of gas were produced:
PV = nRT (remember to put volume in liters and temperature in Kelvin)
(0.975 atm) (.193 L) = n (.0821 L atm / mol K) (298 K)
n = (0.975 atm) (.193 L) / (.0821 L atm / mol K) (298 K)
n = 7.69 X 10-4 mol
Use the number of moles and the molecular weight of oxygen to find out how many grams of oxygen were collected.
(7.69 X 10-4 mol) (32.0 g / 1 mol) = 2.46 X 10-2 g
molecule (hope this helps :))
The balanced chemical reaction is written as:
2H2+O2 = 2H2O
We are given the amount of H2 gas to be used in the reaction. This will be used as the starting point for the calculations. We calculate as follows:
.050 L H2 ( 1 mol H2 / 22.4 L H2 ) ( 1 mol O2 / 2 mol H2 ) ( 22.4 L / 1 mol ) = 0.025 L O2 or 25 mL O2
Empirical formula is the simplest ratio of whole numbers of components making up a compound.
empirical formula can be calculated as follows
C H O
mass 12.0 g 2.00 g 5.33 g
number of moles
12.0 g / 12 g/mol 2.00 g / 1 g/mol 5.33 g / 16 g/mol
= 1.00 mol = 2.00 mol = 0.333 mol
divide by the least number of moles
1.00 / 0.333 2.00 / 0.333 0.333/ 0.333
= 3.00 = 6.01 = 1.00
the number of atoms
C - 3
H - 6
O - 1
empirical formula is C₃H₆O
