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mrs_skeptik [129]
3 years ago
7

Be sure to answer all parts. Carbon disulfide, a poisonous, flammable liquid, is an excellent solvent for phosphorus, sulfur, an

d some other nonmetals. A kinetic study of its gaseous decomposition reveals these data: Experiment Initial [CS2] (mol/L) Initial Rate (mol/L·s) 1 0.100 2.7 × 10−7 2 0.080 2.2 × 10−7 3 0.055 1.5 × 10−7 4 0.044 1.2 × 10−7 (a) Choose the rate law for the decomposition of CS2. Rate = k k[CS2] k[CS2]2 k[CS2]3 (b) Calculate the average value of the rate constant. Enter your answer in scientific notation. × 10 s−1
Chemistry
1 answer:
sveticcg [70]3 years ago
4 0

Explanation:

Experiment Initial [CS2] (mol/L) Initial Rate (mol/L·s)

1 0.100 2.7 × 10−7

2 0.080 2.2 × 10−7

3 0.055 1.5 × 10−7

4 0.044 1.2 × 10−7

a) Choose the rate law for the decomposition of CS2.

Comparing equations 1 and 3, reducing the initial concentration by almost half (from 0.100 to 0.055) leads too the rate of reaction to be reduced by almost half (from 2.7 × 10−7 to 1.5 × 10−7).

This signifies that the reaction is a first order reaction.

Rate = k [CS2]

(b) Calculate the average value of the rate constant.

Taking equation 1.

Rate = k [CS2]

k = Rate / [CS2]

k = 0.100 / (2.7 × 10−7)  = 0.037 x 10^8 = 3.7 x 10^6s-1

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The following pairs of soluble solutions can be mixed. In some cases, this leads to the formation of an insoluble precipitate. D
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There are the insoluble precipitates of CaCo_{3}  forms.

c) Li_{2}S and MnBr_{2} :

There are the insoluble precipitates of MnS  forms.

d) Ba(No_{3} )_{2} and Ag_{2} So_{4} :                        

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There are no insoluble precipitate forms.

b)

Solubility rule suggests:- Ca Cl_{2} ⇒ soluble, (NH_{4} )_{2} Co_{3} ⇒ soluble.

                                        CaCo_{3} ⇒ insoluble, NH_{4} Cl  ⇒ soluble.

There are the insoluble precipitates of CaCo_{3}  forms.

c)

Solubility rule suggests:- Li_{2}S ⇒ soluble, MnBr_{2} ⇒ soluble.

                                        LiBr ⇒ soluble, MnS  ⇒ insoluble.

There are the insoluble precipitates of MnS  forms.

d)

Solubility rule suggests:- Ba(No_{3} )_{2} ⇒ soluble, Ag_{2} So_{4} ⇒insoluble.

                                     

As Ag_{2} So_{4} is insoluble, therefore no precipitate forms.

e)

Solubility rule suggests:- Rb_{2}Co_{3} ⇒ soluble, NaCl ⇒ soluble.

                                        RbCl ⇒ soluble, Na_{2} Co_{3}  ⇒ soluble.

There are no insoluble precipitates forms.

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