(8x 2 −15x)−(x 2 −27x)=ax 2 +bxleft parenthesis, 8, x, squared, minus, 15, x, right parenthesis, minus, left parenthesis, x, squ
quester [9]
Answer:
<h2>5</h2>
Step-by-step explanation:
Given the expression (8x² −15x)−(x² −27x) = ax² +bx, we are to determine the value of b-a. Before we determine the vwlue of b-a, we need to first calculate for the value of a and b from the given expression.
On expanding the left hand side of the expression we have;
= (8x² −15x)−(x² −27x)
Open the paranthesis
= 8x² −15x−x²+27x
collect the like terms
= 8x²−x²+27x −15x
= 7x²+12x
Comparing the resulting expression with ax²+bx
7x²+12x = ax²+bx
7x² = ax²
a = 7
Also;
12x = bx
b =12
The value of b - a = 12 - 7
b -a = 5
Hence the value of b-a is equivalent to 5
Check the picture below
in case you want to know how to get who's the adjacent or opposite, notice in the picture, if you put your eye on the angle itself, what you'd be facing is the opposite side, the adjacent is the side touching the angle.
The last one, since one depends on the other
Answer:
120.96$
Step-by-step explanation:
150$ - 25% = 112$
112$ + 8% = 120.96$
Hope this helps!!
Answer:
4 hours
Step-by-step explanation:
120-72=48
48÷12=4
