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____ [38]
2 years ago
7

Vhat is the probability of flipping a coin 11 times and getting heads 3 times?

Mathematics
1 answer:
Molodets [167]2 years ago
8 0

Answer:

the answer should be 21 if it's there if I'm wrong let me know

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A rectangular athletic field is three times as long as it is wide. If the perimeter of tje athletic field is 128 yards, what are
Dahasolnce [82]
The length of the field is 48 yard while the width of the field is 16 yards.

My Work/Reasoning:
Say that the width is "x" yards. x
The length of the field is three times longer than the width. 3x
The perimeter of the rectangle is 128 yards. 128
To get the perimeter of a rectangle you multiply the sum of the length and the width by two. 2(x+3x)=128
Then you follow order of operations and add x and 3x. 2*4x=128
Then you multiply. 8x=128
After that, you divide 8 on both sides to get the width (total) in yards. x=32
Then you divide that to get the width. 32/2=16
Finally, to get the length of the field, you multiply the width of the field by three to get its length. 16*3=48
4 0
3 years ago
F(x)=(−x−2)(−2x−3) find the first solution and then the second
harina [27]

X=-2, -3/2

_(-2)-2=0

-2(-3/2)-3=0

5 0
4 years ago
Which of the following functions best describes this graph?
Brrunno [24]

Answer:

i think it is a

Step-by-step explanation:

8 0
3 years ago
How many points are shared by concentric circles?
Soloha48 [4]

Answer:

0

Step-by-step explanation:

By Theorem 10.2, in the same circle or congruent circles, if two chords are equal, then their corresponding minor arcs are congruent. Concentric circles have the same center but the circles do not intersect. Therefore, the number of points shared by concentric circles is 0.

5 0
3 years ago
Read 2 more answers
Determine the margin of error for a 90% confidence interval to estimate the population mean when s = 40 for the sample sizes bel
Ann [662]

Answer:

a) The margin of error for a 90% confidence interval when n = 14 is 18.93.

b) The margin of error for a 90% confidence interval when n=28 is 12.88.

c) The margin of error for a 90% confidence interval when n = 45 is 10.02.

Step-by-step explanation:

The t-distribution is used to solve this question:

a) n = 14

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 14 - 1 = 13

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.7709

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.7709\frac{40}{\sqrt{14}} = 18.93

In which s is the standard deviation of the sample and n is the size of the sample.

The margin of error for a 90% confidence interval when n = 14 is 18.93.

b) n = 28

27 df, T = 1.7033

M = T\frac{s}{\sqrt{n}} = 1.7033\frac{40}{\sqrt{28}} = 12.88

The margin of error for a 90% confidence interval when n=28 is 12.88.

c) The margin of error for a 90% confidence interval when n = 45 is

44 df, T = 1.6802

M = T\frac{s}{\sqrt{n}} = 1.6802\frac{40}{\sqrt{45}} = 10.02

The margin of error for a 90% confidence interval when n = 45 is 10.02.

3 0
3 years ago
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