<img src="https://tex.z-dn.net/?f=4%20%2B%20%20%7B5%7D%5E%7B2%7D%20" id="TexFormula1" title="4 + {5}^{2} " alt="4 + {5}^{2} "

All categories

guajiro [1.7K]

4 years ago

align="absmiddle" class="latex-formula">

Mathematics

2 answers:

Greeley [361]4 years ago

6 0

5 x 5 = 25 + 4 = 29 This is the answer for your equation.

Tju [1.3M]4 years ago

5 0

5 squared is 25. 25+4. Answer is 29

You might be interested in

Which of these statements is correct? A) the distance between the points (-2, -9) and (9, 3) is 11 units B) the distance between

siniylev [52]

The answer is C The distance between the points (15,6) and (21,22)

4 0

3 years ago

I need help with questions #7 and #8 plz

katen-ka-za [31]

Answer:

7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg

8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg

Step-by-step explanation:

Law of Cosines

$c^2 = a^2 + b^2 - 2ab \cos C$

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.

Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.

We use the law of cosines to find C.

$18^2 = 12^2 + 16^2 - 2(12)(16) \cos C$

$324 = 144 + 256 - 384 \cos C$

$-384 \cos C = -76$

$\cos C = 0.2$

$C = \cos^{-1} 0.2$

$C = 78.6^\circ$

Now we use the law of sines to find angle A.

Law of Sines

$\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}$

We know c and C. We can solve for a.

$\dfrac{a}{\sin A} = \dfrac{c}{\sin C}$

$\dfrac{12}{\sin A} = \dfrac{18}{\sin 78.6^\circ}$

Cross multiply.

$18 \sin A = 12 \sin 78.6^\circ$

$\sin A = \dfrac{12 \sin 78.6^\circ}{18}$

$\sin A = 0.6535$

$A = \sin^{-1} 0.6535$

$A = 40.8^\circ$

To find B, we use

m<A + m<B + m<C = 180

40.8 + m<B + 78.6 = 180

m<B = 60.6 deg

I'll use the law of cosines 3 times here to solve for all the angles.

Law of Cosines

$a^2 = b^2 + c^2 - 2bc \cos A$

$b^2 = a^2 + c^2 - 2ac \cos B$

$c^2 = a^2 + b^2 - 2ab \cos C$

Find angle A:

$a^2 = b^2 + c^2 - 2bc \cos A$

$8^2 = 18^2 + 12^2 - 2(18)(12) \cos A$

$64 = 468 - 432 \cos A$

$\cos A = 0.9352$

$A = 20.7^\circ$

Find angle B:

$b^2 = a^2 + c^2 - 2ac \cos B$

$18^2 = 8^2 + 12^2 - 2(8)(12) \cos B$

$324 = 208 - 192 \cos A$

$\cos B = -0.6042$

$B = 127.2^\circ$

Find angle C:

$c^2 = a^2 + b^2 - 2ab \cos C$

$12^2 = 8^2 + 18^2 - 2(8)(18) \cos B$

$144 = 388 - 288 \cos A$

$\cos C = 0.8472$

$C = 32.1^\circ$

8 0

3 years ago

Consider the equation

muminat

Answer:

A. $a=10\\ \\b\neq -8$

B. $a=10\\ \\b= -8$

Step-by-step explanation:

Consider the equation

$2(5x-4) = ax + b$

A. This equation has no solutions when the coefficients at x are the same and the free coefficients are not the same.

First, use distributive property:

$2(5x-4)=2\cdot 5x-2\cdot 4=10x-8$

So, the equation is

$10x-8=ax+b$

This equation has no solutions when

$a=10\\ \\b\neq -8$

B. The equation has infinitely many solutions when the coefficients at x are the same and the free coefficients are the same too.

So, the equation

$10x-8=ax+b$

has infinitely many solutions when

$a=10\\ \\b= -8$

In other cases, the equation has a unique solution

5 0

3 years ago

-8x+2y=-2 4x+4y=-4 What is the solution to the system

pickupchik [31]

The solution to system is x = 0 and y = -1

Solution:

Given system of equations are:

-8x + 2y = -2 ----------- eqn 1

4x + 4y = -4 ---------- eqn 2

We have to solve the system of equations

We can solve the equations by elimination method

Multiply eqn 2 by 2

8x + 8y = -8 ------ eqn 3

Add eqn 1 and eqn 3

-8x + 2y = -2

8x + 8y = -8

( + ) ---------------

0x + 2y + 8y = -2 - 8

10y = -10

Divide both sides by 10

y = -1

Substitute y = -1 in eqn 1

-8x + 2(-1) = -2

-8x - 2 = -2

-8x = -2 + 2

x = 0

Thus the solution to system is x = 0 and y = -1

3 0

3 years ago

Factor completely x2 + 8x - 20

kvv77 [185]

X-2
Hope this helps!
Vote me brainliest!

3 0

3 years ago

Read 2 more answers