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inysia [295]
2 years ago
14

)Line CP is a perpendicular bisector to line segment AB. If

Mathematics
1 answer:
Nina [5.8K]2 years ago
3 0

Answer:

Step-by-step explanation:

Line CP is a perpendicular bisector to line segment AB

if

two congruent lines are formed when AB is intersected ( bisector forms two equal in measure and congruent parts)

and

a right angle is formed between the line CP and AB ( perpendicular lines form right angles.)

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y=-4x-6

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Question 17 of 25
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An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref
hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}

So the cost of laying pipe under water with this distance is

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And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

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We can find the minimum value of this by taking the 1st derivative and set it to 0

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We can move the first term over to the right hand side and divide both sides by 400000

1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}

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From here we can square up both sides

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9 - 6d + d^2 + 4 = 36 - 24d + 4d^2

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(d - 3)^2 = 0

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So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

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3 years ago
Solve by factoring. m^2+8m+7=0 A. 8,7 B. -7,1 C. -7,-1 D. 7,1
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The answer is c, -1 or -7

Hope this helped :)
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