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3 years ago

Find the solution to the system of equations given below: x=-4 -5x-4y=16 PLS HELP

Mathematics

1 answer:

poizon [28]3 years ago

8 0

Answer:

Step-by-step explanation:

Since x=-4 plug in the -4 into the equation to find y,

-5(-4)-4y=16

20-4y=16 -20 -20 __________

-4y=-4

-4y/-4=-4/-4

___________

y=1

So now you found both x and y so plug in both now to check if both are correct.

-5(-4)-4(1)=16

20-4=16

16=16

So both y and x are correct.

Hope this helps!:)

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Amanda is reading a book that has 125 pages. she has read 12 pages a day for 4 days in a row. how many more pages does amanda ha

FinnZ [79.3K]

Total pages=125
Pages read in 1 day=12
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3 years ago

Find x 5x-7+8x-55 13 POINTS Show work please

Law Incorporation [45]

Combine like terms. The 5x is grouped to the 8x and the -7 isgrouped with the -55.

This means 5x + 8x = 13x and -7 - 55 = -62

The new expression is 13x - 62. We can't find the exact value of x because the expression wasn't set equal to anything.

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4 years ago

Read 2 more answers

What 5.00 times 0.75 equal

xeze [42]

We know that 75=5*5*3 so
5*5*3 times 5=125*3=375 then move the decimal place two places to the left (divide by 100) and get 3.75

or you could note that 0.75=3/4 so
3/4 times 5=
15/4
simplified=3 and 3/4

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3 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .