The period is equal to 2pi/n, where n is the coefficient of t. In this case pi/2. Therefore the period in this example is 4. Frequency is equal to 1/period. Hence the frequency for this problem is 1/4
Answer:
JK=7
Step-by-step explanation:
From the line segment, since J is on it ,it means the line segment is
represented as I J K
from this illustration, we can say that the longest part of the line segment is from I to K
this means that, IJ +JK =IK
making JK the subject,
JK= IK - IJ
but from the question, JK=2x-1 , IK=3x+2 and IJ=3x-5
substituting them in the expression,
2x-1 =3x+2 -(3x-5)
solving for x
2x-1 =3x+2-3x+5
2x-1 =0+7
2x-1 =7
2x=1+7
2x=8
dividing through by 2
2x/2 =8/2
x=4
but the question says we should find the numerical value for JK
but from the line segment,
JK=2x-1
but now we know the value of x to be 2
so substituting it in the formula
JK= 2(4)-1
JK=8-1
JK=7
therefore, the numerical value for JK is 7
Trigonometry can be used to find angles and sides of simple triangles. If an 18-foot ladder touches a building 14 feet up the wall then the angle can be deduced by trigonometry. In this case, the ladder defines the hypotenuse (H) of the triangle and the wall defines the opposite (O) side of the triangle. Therefore we can use the equation theta=sin^-1(O/H) . This yields an angle of 51 degrees.
2(x+5) =20 is the translation
Answer:
Distance = 660 meters
Step-by-step explanation:
Given the following data;
Radius, r = 21 m
Number of revolutions = 5 times
To find the distance covered;
The distance covered in one revolution is given by the circumference of a circle.
Mathematically, circumfeence of a circle is equal to;
C = 2πr
Substituting into the formula, we have;
C = 2 * 22/7 * 21
C = 44 * 3
C = 132 meters
Next, we find the distance covered;
Distance = Circumference * Number of revolutions
Distance = 132 * 5
Distance = 660 meters
