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ipn [44]
3 years ago
13

suppose you flip a coin twice. what is the probability that you get tails on the first flip and tail on the second flip?

Mathematics
2 answers:
soldi70 [24.7K]3 years ago
8 0
<span>You can count all the possibilities(sample space) for tossing a coin twice. Possibilities are: HH HT TT TH. So there are four possible outcomes and only one satisfies your demand i.e. HT. Hence probability of getting HT = 1/4.Now let’s solve it in more conceptual way. Suppose you toss a single coin then P(H) = 1/2 and P(T) = 1/2 assuming that coins is not biased. When you toss a coin twice, the second event is independent of first event. Therefore P(HT) = P(H).P(T) = 1/4.</span>

Hopefully.! You got your answer.

Nezavi [6.7K]3 years ago
4 0
The possibilities are HH TT HT TH so to get TT you have a 1/4 chance (25%)
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Answer:

-$13.5

Step-by-step explanation:

Let x be a random variable of a count of player gain.

- We are told that if the die shows 3, the player wins $45.

- there is a charge of $9 to play the game

If he wins, he gains; 45 - 9 = $36

If he looses, he has a net gain which is a loss = -$9

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Thus;

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a(x) = x^2 + 24 x + 16 x + 24\times 16

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