Expanding
-3h-15+2=4h+24-9
-3h-4h=24-9-2+15
-7h=28
h=4
Hi,
AxB = 0 means A=0. or B=0
so 2 solutions :
4x-3= 0
4x=3
x = 3/4
and x+2 = 0.
x= -2
solutions are : -2 +and 3/4
Answer:
The value of the expression given is:
Step-by-step explanation:
First, you must divide the expression in three, and to the final, you can multiply it:
- [(3^8)*(2^(-5))*(9^0)]^(-2)
- [(2^(-2))/(3^3)]^4
- 3^28
Now, we can solve each part one by one:
<em>First part.
</em>
- 3^8 = 6561
- 2^(-5) = 0.03125
- 9^0 = 1 (Whatever number elevated to 0, its value is 1)
- (6561 * 0,03125 * 1) = 205.03125
And we elevate this to -2:
- 205.03125^-2 = 2<u>.378810688*10^(-5)</u> or <u>0.00002378810688
</u>
<em>Second part.
</em>
- 2^(-2) = 0.25
- 3^3 = 27
- 0.25 / 27 = 9.259259259 * 10^(-3) or 0.00925925925925
And we elevate this to 4:
- 0.00925925925925^4 = <u>7.350298528 * 10^(-9)</u> or <u>0.000000007350298528
</u>
<em>Third Part.
</em>
- 3^28 = <u>2.287679245 * 10^13</u> or <u>22876792450000</u>
At last, we multiply all the results obtained:
- 0.00002378810688 * 0.000000007350298528 * 22876792450000 = <u>3.999999999999999999</u> approximately <u>4</u>
<u><em>We approximate the value because the difference to 4 is minimal, which could be obtained if we use all the decimals in each result</em></u>.
Answer:
x=32 so one solution only
Step-by-step explanation:
6(x-8)+10=5x-6
6x-48+10=5x-6
6x-38=5x-6
x-38=-6
x=32
Therefore, the equation only has one solution which is x=32
Answer:
<em>We disagree with Zach and Delia and agree with Alicia</em>
Step-by-step explanation:
The domain of a function is the set of values of the independent variable that the function can take according to given rules or restrictions.
The range is the set of values the dependent variable can take for every possible value of the domain.
The graph shows a continuous line representing the values of the function. We must take a careful look to the values of x (horizontal axis) where the function exists. It can be done by drawing an imaginary vertical line passing through the value of x. If that line touches the graph of the function, it belongs to the domain. It's clear that every value of x between -5 and 3 (both inclusive because there are solid dots in the extremes) belong to the domain:
Domain: 
The range is obtained in a similar way as the domain, but the imaginary lines must be horizontal. That gives us the values of y range from -7 to 5 both inclusive:
Range:
Thus we disagree with Zach and Delia and agree with Alicia
